loops - 循环日期范围

Question

在 Python3 中，我可以像这样遍历一系列日期

import datetime

dt0 = datetime.datetime(2017, 1, 1, 0, 0, 0)
dt1 = datetime.datetime(2017, 1, 5, 0, 0, 0)
dt = dt0
while dt <= dt1:
    print(dt.strftime("%Y-%m-%d %H:%M:%S"))
    dt += datetime.timedelta(days=1)

在 Rust 中是否有类似的方法来循环日期？ 我知道我可以在几个月内然后在一个月内的几天内编写一个嵌套循环。像这样:

let days = [1, 2, 3, 4, 5, 6, 7,
            8, 9, 10, 11, 12, 13, 14, 
            15, 16, 17, 18, 19, 20, 21,
            22, 23, 24, 25, 26, 27, 28, 29, 30, 31];
let months = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12];
let months_30_days = [4, 6, 9, 11];

for month in months.iter() {
    for day in days.iter() {
        if month == &2 {
            if is_leap_year(year) {
                if day > &29 {
                    continue;
                }
            } else if day > &28 {
                continue;
            }
        } else if months_30_days.contains(&month) && day > &30 {
            continue;
        }

        print!("{:04}-{:02}-{:02} ", year, month, day);
    }
}

fn is_leap_year(year: i32) -> bool {
    if year % 100 == 0 {
        return year % 400 == 0;
    } else {
        return year % 4 == 0;
    }
}

有没有更质朴的方式来做到这一点？

Answer 1

您可以使用 chrono crate :

extern crate chrono; // 0.4.6

use chrono::{Duration, TimeZone, Utc};

fn main() {
    let dt0 = Utc.ymd(2017, 1, 1);
    let dt1 = Utc.ymd(2017, 1, 5);

    let mut dt = dt0;
    while dt <= dt1 {
        println!("{:?}", dt);
        dt = dt + Duration::days(1);
    }
}

这也可以包装成一个迭代器:

extern crate chrono; // 0.4.6

use chrono::{Date, Duration, TimeZone, Utc};
use std::mem;

struct DateRange(Date<Utc>, Date<Utc>);

impl Iterator for DateRange {
    type Item = Date<Utc>;
    fn next(&mut self) -> Option<Self::Item> {
        if self.0 <= self.1 {
            let next = self.0 + Duration::days(1);
            Some(mem::replace(&mut self.0, next))
        } else {
            None
        }
    }
}

fn main() {
    let dt0 = Utc.ymd(2017, 1, 1);
    let dt1 = Utc.ymd(2017, 1, 5);

    for dt in DateRange(dt0, dt1) {
        println!("{:?}", dt);
    }
}