我只是想显示具有相同 GROUP_CONCAT() 列值的行。最后使用 GROUP BY 时，由于 GROUP BY 国家/地区，它只显示表中的最后一个全名。当我按国家/地区分组时是否仍然可以显示所有行？ 这是我的 sql:
SELECT firstname, lastname, country, COUNT(*) c
FROM (
SELECT firstname, lastname,
GROUP_CONCAT(
DISTINCT f.countryname
ORDER BY f.countryname ASC
SEPARATOR ','
) AS country
FROM person p
INNER JOIN favoritecountry f
ON p.id = f.id
GROUP BY firstname, lastname
) t
GROUP BY country
HAVING c > 1
ORDER BY c DESC;
我的结果是:
+-----------+----------+--------------+---+
| firstname | lastname | country | c |
+-----------+----------+--------------+---+
| bill | smith | Poland,Spain | 2 |
+-----------+----------+--------------+---+
相反，我想要这样的东西:
+-----------+----------+--------------+---+
| firstname | lastname | country | c |
+-----------+----------+--------------+---+
| bill | smith | Poland,Spain | 2 |
| phil | cooper | Poland,Spain | 2 |
+-----------+----------+--------------+---+
SQL 新手，所以需要一些帮助
最佳答案
根据您的预期结果，您应该交叉加入 group_concat country 的计数和 country 的名称
select t2.firstname, t2.lastname, t2.country
from (
SELECT firstname, lastname,
GROUP_CONCAT(
DISTINCT f.countryname
ORDER BY f.countryname ASC
SEPARATOR ','
) AS country
FROM person p
INNER JOIN favoritecountry f
ON p.id = f.id
GROUP BY firstname, lastname
) t2
cross join (
select t1.country, count(*) my_count
from (
SELECT firstname
, lastname,
GROUP_CONCAT( DISTINCT f.countryname
ORDER BY f.countryname ASC
SEPARATOR ','
) AS country
FROM person p
INNER JOIN favoritecountry f ON p.id = f.id
GROUP BY firstname, lastname
) t
) t1 on t1.country = t2.country
关于mysql - GROUP BY 列 HAVING COUNT(*) > 1，仍然显示所有行？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54672115/