PHP 并将 MySQL 行封装到 JSON 数组中

Question

我正在玩一个留言簿/聊天室的想法，并且有一个包含三列的 MySQL 表设置:

1 - id - 主键自增

2 - 名称 - 字符串

3 - 注释 - 字符串

我对 PHP 的经验很少，但这是我为这个操作准备的:

$result = mysql_query("SELECT * FROM guestbook");
$i = 0;
while($row = mysql_fetch_array($result))
  {
      //add the row to the $chat array at specific index of $i
      $chat[$i] = $row;
      $i += 1;
  }

$encode = json_encode($chat);
echo "$encode";

但是，这个输出看起来很糟糕:

[{"0":"1","id":"1","1":"Justin ","name":"Justin ","2":"Comment 1","comment":"Comment 1"},
{"0":"2","id":"2","1":"Justin ","name":"Justin ","2":"Another comment","comment":"Another comment"},
{"0":"3","id":"3","1":"Justin ","name":"Justin ","2":"Look at this comment!","comment":"Look at this comment!"},
{"0":"4","id":"4","1":"Justin ","name":"Justin ","2":"Ok I'm done talking","comment":"Ok I'm done talking"}]

我希望获得三个字段:id、name 和 comment，但看起来事情翻了一番。谁能帮忙？

谢谢!

Answer 1

套用 Marc 的话，只需替换这一行:

while($row = mysql_fetch_array($result))

有了这个:

while($row = mysql_fetch_array($result, MYSQL_ASSOC))

为了获得更清晰的 JSON。默认情况下，mysql_fetch_array() 将返回整数索引和关联索引，您只需要关联索引。