php - 需要适本地在 CSV 中标题标题，而不是使用表列标题

Question

我有一个将表格导出到 CSV 文件的功能，然后我使用电子表格应用程序打开该文件。

有没有办法设置 CSV 的标题以适本地命名每一列。

例如:

我有一个包含名字、姓氏、电子邮件和评论的表格。

表格设置为:fname, lname, email, comments

所以表导出为:

fname, lname, email, comments
john, doe, johndoe@email.com, I am John Doe this is my comment

我想将 header (fname、lname、email、comments)更改为更具可读性的内容，所以它会像这样:

First Name, Last Name, Email, Comments
john, doe, johndoe@email.com, I am John Doe this is my comment

这是我的代码:

function exportNamesCommentsCSV($table,$filename = 'volunteer_2009_comments.csv') {
    $csv_terminated = "\n";
    $csv_separator = ",";
    $csv_enclosed = '"';
    $csv_escaped = "\\";
    $sql_query = "select lname, fname, comments from volunteers_2009";

    // Gets the data from the database
    $result = mysql_query($sql_query);
    $fields_cnt = mysql_num_fields($result);

    $schema_insert = '';

    for ($i = 0; $i < $fields_cnt; $i++) {
        $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
            stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
        $schema_insert .= $l;
        $schema_insert .= $csv_separator;
    } // end for

    $out = trim(substr($schema_insert, 0, -1));
    $out .= $csv_terminated;

    // Format the data
    while ($row = mysql_fetch_array($result)) {
        $schema_insert = '';
        for ($j = 0; $j < $fields_cnt; $j++) {
            if ($row[$j] == '0' || $row[$j] != '') {

                if ($csv_enclosed == '') {
                    $schema_insert .= $row[$j];
                } else {
                    $schema_insert .= $csv_enclosed . 
                    str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
                }
            } else {
                $schema_insert .= '';
            }

            if ($j < $fields_cnt - 1) {
                $schema_insert .= $csv_separator;
            }
        } // end for

        $out .= $schema_insert;
        $out .= $csv_terminated;
    } // end while

    header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
    header("Content-Length: " . strlen($out));
    header("Content-type: text/x-csv");
    header("Content-Disposition: attachment; filename=$filename");
    echo $out;
    exit;
}

Answer 1

CSV 文件的标题只是第一行。所以你会改变这个 block :

for ($i = 0; $i < $fields_cnt; $i++) {
    $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
            stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
    $schema_insert .= $l;
    $schema_insert .= $csv_separator;
} // end for

$out = trim(substr($schema_insert, 0, -1));
$out .= $csv_terminated;

您可以将其更改为非常简单的内容，如下所示:

$out .= "First Name, Last Name, Email, Comments\n";

除非我完全误解了你的问题。

编辑:您的示例代码显示了一个特定的查询。如果它需要为多个查询工作，您将必须找到这些友好名称的来源。例如，您可以将名称作为参数传递或 store them in the database .