mysql - 使用 MySQL ORDER BY 选择范围

Question

所以我有这个游戏数据库，其中有几个带有字段、id、名称、积分的用户

我需要一个特定用户的排名表，其中可以看到其位置与积分的关系，表中有 8 个位置的空间，所以我正在寻找一种方法来执行以下操作:

如果我执行SELECT * FROM users WHERE id = {user_id} ORDER By points 选择此 id 之前的 4 个结果和之后的 3 个结果。有一个查询可以做到这一点吗？结果应如下所示:

---------------------
|id   |name  |points|
---------------------
| 52  |name1 | 10   |
---------------------
| 23  |name1 | 09   |
---------------------
| 93  |name1 | 08   |
---------------------
| 12  |name1 | 07   |
---------------------
| 43  |queried_name1 | 06   |
---------------------
| 67  |name1 | 05   |
---------------------
| 32  |name1 | 04   |
---------------------
| 91  |name1 | 03   |
---------------------

我试图通过软件来实现这一点，但是迭代所有结果的速度非常慢。感谢您的帮助!

Answer 1

对于上面的结果，我想说:

SELECT * FROM users WHERE points > (SELECT points FROM users WHERE id = {user_id}) ORDER By points ASC LIMIT 3;

对于以下结果:

SELECT * FROM users WHERE points < (SELECT points FROM users WHERE id = {user_id}) ORDER By points DESC LIMIT 4;

因此，有了一个大联盟，它会给出:

SELECT * FROM (SELECT * FROM users WHERE points > (SELECT points FROM users WHERE id = {user_id}) ORDER By points ASC LIMIT 3 ) a 
UNION
SELECT * FROM users WHERE id = {user_id}
UNION
SELECT * FROM (    SELECT * FROM users WHERE points < (SELECT points FROM users WHERE id = {user_id}) ORDER By points DESC LIMIT 4 ) b