我有以下代码
SELECT PRESENTERS.PNRFNAME, PRESENTERS.PNRLNAME,
COUNT(EPISODES.PRESENTERID) AS "no. of episodes"
FROM EPISODES
JOIN PRESENTERS
ON EPISODES.PRESENTERID=PRESENTERS.PRESENTERID
GROUP BY PRESENTERS.PNRFNAME, PRESENTERS.PNRLNAME
ORDER BY COUNT(EPISODES.PRESENTERID)
我尝试添加
HAVING COUNT(EPISODES.PRESENTERID) > 2
但我必须假装我没有看到有多少个“不”。剧集都在那里。还有其他方法可以显示有更多剧集的行吗?情节?
最佳答案
select top 1 PRESENTERS.PNRFNAME, PRESENTERS.PNRLNAME,COUNT(EPISODES.PRESENTERID) AS "no. of episodes" FROM EPISODES JOIN PRESENTERS ON EPISODES.PRESENTERID=PRESENTERS.PRESENTERID GROUP BY PRESENTERS.PNRFNAME, PRESENTERS.PNRLNAME ORDER BY COUNT(EPISODES.PRESENTERID) desc;
关于mysql - 我想显示最高的号码。剧集数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38889342/