我在将带有通配符的 LIKE
绑定(bind)到我在 MySQLi 中准备好的语句时遇到问题。我尝试了以下两种方法,如下所示 & concat。(使用@fancyPants 输入更新)
绑定(bind)后有没有办法查看自己的SQL语句?
如何正确绑定(bind)它以获得我想要的结果?
它在没有 LIKE 语句的情况下工作。
我只能从使用特定搜索词中提取数据。我的代码有什么问题吗?
$str = $_POST["searchstr"];
if(isset($_POST['submit']))
{
$price=$_POST['price'];
if(!empty($_POST['chkbx']))
{
foreach($_POST['chkbx'] as $selected)
{
$sql= 'SELECT bookTitle, bookPrice FROM nbc_book WHERE catID LIKE "%'.$selected.'%" AND bookTitle LIKE "%'.$str.'%" AND bookPrice < ?';
$stmt=mysqli_prepare($con,$sql);
mysqli_stmt_bind_param($stmt,"i",$price);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $bookTitle, $bookPrice);
while ($stmt->fetch()) {
echo $bookTitle.$bookPrice."<br>";
}
}
}
}
最佳答案
$searchStr = 'oracle';
$sql= 'SELECT bookTitle, bookPrice FROM nbc_book WHERE catID LIKE ? AND bookTitle LIKE "%'.$searchStr.'%" AND bookPrice < ?';
$stmt=mysqli_prepare($con,$sql);
mysqli_stmt_bind_param($stmt,"ssi",$selected,$price);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $bookTitle, $bookPrice);
while ($stmt->fetch()) {
echo $bookTitle;
}
关于php - mySqli 绑定(bind)参数 LIKE 与通配符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26543097/