如何用 mysql 中具有相同数据的 5 行替换一行。例如,我有这个表
id | companyId | name | open | close
1 | 1 | mon-fri | 10:00 | 19:00
2 | 1 | sat | 10:00 | 12:00
3 | 1 | sun | 10:00 | 12:00
4 | 2 | mon-fri | 10:00 | 16:00
5 | 2 | sat | 10:00 | 13:00
6 | 2 | sun | 10:00 | 13:00
我想将 mon-fri 的名称字段转换为 mon 、 tues 、 wed 、 thur 、 fri 。
id | companyId | name | open | close
1 | 1 | mon | 10:00 | 19:00
2 | 1 | tues | 10:00 | 19:00
3 | 1 | wed | 10:00 | 19:00
4 | 1 | thur | 10:00 | 19:00
5 | 1 | fri | 10:00 | 19:00
6 | 1 | sat | 10:00 | 12:00
7 | 1 | sun | 10:00 | 12:00
.
.
.
最佳答案
您无法通过 UPDATE
来做到这一点,但您可以做的是使用一些字符串文字进行一系列 INSERT INTO ... SELECT
,然后通过 DELETE
删除展开的行。
/* First insert a row for each mon,tue,wed,thur,fri */
/* Column values are copied from the existing mon-fri row, and use the literal strings 'mon', 'tue', etc as the new `name` */
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT `companyId`, 'mon', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT `companyId`, 'tue', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT `companyId`, 'wed', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT `companyId`, 'thur', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT `companyId`, 'fri', `open`, `close` FROM yourtable WHERE `name` = 'mon-fri'
/* Then delete the original mon-fri rows which you just expanded out */
DELETE FROM yourtable WHERE `name` = 'mon-fri'
http://sqlfiddle.com/#!2/cae33/1
(应得的:这个出色的建议是 Andriy M 在未经请求的编辑中完成的)
您还可以通过使用虚拟表来减少语句数量以及表扫描数量,如下所示:
/* Cross-join the existing 'mon-fri' rows with a virtual table of day names
of 'mon' through 'fri' and insert the resulting set back into your table */
INSERT INTO yourtable (`companyId`, `name`, `open`, `close`)
SELECT t.`companyId`, v.`name`, t.`open`, t.`close`
FROM yourtable t
CROSS JOIN (
SELECT 'mon' AS `name` UNION ALL
SELECT 'tue' UNION ALL
SELECT 'wed' UNION ALL
SELECT 'thur' UNION ALL
SELECT 'fri'
) v
WHERE t.`name` = 'mon-fri';
/* Then delete the original mon-fri rows which you just expanded out */
DELETE FROM yourtable WHERE `name` = 'mon-fri';
http://sqlfiddle.com/#!2/98e35/1
评论后更新:
插入行时强制其顺序没有实际值(value),最好在 SELECT
中完成。
要按天为每个companyId
订购,无论采用哪种方式都需要做一些工作。您可以使用 %a
调用 LOWER(STR_TO_DATE())
并比较工作日值,但是您还需要将 thur
更改为 thu
因为这是 MySQL 的缩写方式。这会导致一堆函数调用。
相反,您可以在 ORDER BY
中使用 CASE....
为每一天分配序数值,例如:
ORDER BY
companyId,
CASE `name`
WHEN 'sun' THEN 1
WHEN 'mon' THEN 2
WHEN 'tue' THEN 3
WHEN 'wed' THEN 4
WHEN 'thur' THEN 5
WHEN 'fri' THEN 6
WHEN 'sat' THEN 7
ELSE 8 END
上述方法都不会对索引友好。
如果您需要提高性能,我建议不要首先存储字符串'mon'、'tue'、'wed'
等,而是存储它们关联的工作日值(value)。请参阅DAYOFWEEK()
了解详情。
关于mysql - 在mysql中用2行替换一行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13895726/