我从用户那里获取了一个物理位置地址,并尝试将其安排为创建一个 URL,该 URL 稍后将用于从 Google Geocode API 获取 JSON 响应。
最终的 URL 字符串结果应该类似于 this one , 没有空格:
我不知道如何替换我的 URL 字符串中的空格并使用逗号代替。我确实阅读了一些关于字符串和正则表达式包的信息,并创建了以下代码:
package main
import (
"fmt"
"bufio"
"os"
"http"
)
func main() {
// Get the physical address
r := bufio.NewReader(os.Stdin)
fmt.Println("Enter a physical location address: ")
line, _, _ := r.ReadLine()
// Print the inputted address
address := string(line)
fmt.Println(address) // Need to see what I'm getting
// Create the URL and get Google's Geocode API JSON response for that address
URL := "http://maps.googleapis.com/maps/api/geocode/json?address=" + address + "&sensor=true"
fmt.Println(URL)
result, _ := http.Get(URL)
fmt.Println(result) // To see what I'm getting at this point
}
最佳答案
您可以使用 strings.Replace
.
package main
import (
"fmt"
"strings"
)
func main() {
str := "a space-separated string"
str = strings.Replace(str, " ", ",", -1)
fmt.Println(str)
}
如果您需要更换不止一件东西,或者您需要一遍又一遍地进行相同的更换,最好使用 strings.Replacer
:
package main
import (
"fmt"
"strings"
)
// replacer replaces spaces with commas and tabs with commas.
// It's a package-level variable so we can easily reuse it, but
// this program doesn't take advantage of that fact.
var replacer = strings.NewReplacer(" ", ",", "\t", ",")
func main() {
str := "a space- and\ttab-separated string"
str = replacer.Replace(str)
fmt.Println(str)
}
当然,如果您出于编码目的进行替换,例如 URL 编码,那么最好使用专门用于该目的的函数,例如 url.QueryEscape
关于string - 如何在 Golang 中替换字符串中的单个字符?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8190540/