mysql - 使用 if 和 while 循环时在错误的位置拆分表

Question

我正在尝试显示 2 个表，1 个用于节目，1 个用于电影，但目前它每条记录显示 1 个表

这是页面 http://starsqa.com/ana-lucasey-about

这是新的代码片段:

  if ($result['order'] == 1 OR $result['order'] == 2 OR $result['order'] == 6 OR $result['order'] == 4) {
            $qry_stringr = "SELECT roles.starID, starName, roles.knownFor, roles.`character`, roles.`year`, most, type FROM roles INNER JOIN stars ON roles.starID = stars.starID WHERE roles.starID = {$result['starID']} ORDER BY roles.`year` DESC";
            $prepr = $pdo_conn->prepare($qry_stringr);
            $prepr->execute(array());

        $showsArray = array();
        $moviesArray = array();

 while ($rowr = $prepr->fetch(PDO::FETCH_ASSOC)) {
      if ($rowr['type'] == 0) {
         $showsArray[] = $rowr;
      }
      else if($rowr['type'] == 1) {
         $moviesArray[] = $rowr;
      }
 }
echo "<table border='1' bgColor='white'><tbody><tr bgColor='lightgrey' style='color:black;'><td><b>Show</b></td><td><b>Role</b></td><td><b>Year</b></td></tr>";
 foreach($showsArray as $row) {
                    $most = $rowr['most'] == 1 ? ' color:#DE5635;' : '' OR $rowr['most'] == 0 ? ' color:black;' : '';
                    echo "<tr><td><font style='{$most}'>{$rowr['knownFor']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                          <td><font style='{$most}'>{$rowr['character']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                          <td><font style='{$most}'>{$rowr['year']}</font></td></tr>";
                    echo "</tbody>";
 }
 echo "</table><br><br>";
echo "<table border='1' bgColor='white'><tbody><tr bgColor='lightgrey' style='color:black;'><td><b>Movie</b></td><td><b>Role</b></td><td><b>Year</b></td></tr>";
 foreach($moviesArray as $row) {
                    $most = $rowr['most'] == 1 ? ' color:#DE5635;' : '' OR $rowr['most'] == 0 ? ' color:black;' : '';
                    echo "<tr><td><font style='{$most}'>{$rowr['knownFor']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                          <td><font style='{$most}'>{$rowr['character']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                          <td><font style='{$most}'>{$rowr['year']}</font></td></tr>";
                    echo "</tbody>";
 }
 echo "</table><br><br>"; 
 }

Answer 1

您正在为每一行创建一个表格。如果查看 while 循环，您会发现对于数据的每次迭代，您都在创建一个新表。有很多方法可以解决这个问题，我会创建两个数组，一个用于节目，一个用于电影。在循环期间，将行添加到适当的数组中。毕竟，遍历每个数组以创建您的表。

例如:

 $showsArray = array();
 $moviesArray = array();

 while ($rowr = $prepr->fetch(PDO::FETCH_ASSOC)) {
      if ($rowr['type'] == 0) {
         $showsArray[] = $rowr;
      }
      elseif($rowr['type'] == 1) {
         $moviesArray[] = $rowr;
      }
 }
 echo "<table border='1' bgColor='white'><tbody><tr bgColor='lightgrey' style='color:black;'><td><b>Show</b></td><td><b>Role</b></td><td><b>Year</b></td></tr>";
 foreach($showsArray as $row) {
     //create the table row here.
 }
 echo "</table>";
echo "<table border='1' bgColor='white'><tbody><tr bgColor='lightgrey' style='color:black;'><td><b>Movie</b></td><td><b>Role</b></td><td><b>Year</b></td></tr>";
 foreach($moviesArray as $row) {
     //create the table row here.
 }
 echo "</table>";

另一种方法是在 while 循环期间，而不是使用 echo，将 HTML 附加到一个变量，然后在循环后输出它。

$movies = "";
$shows = "";
while ($rowr = $prepr->fetch(PDO::FETCH_ASSOC)) {
        echo "{$rowr['type']} - {$rowr['knownFor']}    ";
        if ($rowr['type'] == 0) {
            $shows .= "<tr><td><font>{$rowr['knownFor']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                  <td><font>{$rowr['character']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                  <td><font>{$rowr['year']}</font></td></tr>";
            $shows .= "</tbody></table><br><br>";
        }
        if ($rowr['type'] == 1) {
            $movies .= "<tr><td><font>{$rowr['knownFor']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                  <td><font>{$rowr['character']}&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</font></td>
                  <td><font>{$rowr['year']}</font></td></tr>";
            $movies .= "</tbody></table>";
        }
    }
   //add code here to create your
   //tables and echo $shows and $movies in the appropriate places.