php - 如何使用php比较文件中的两个mysql表结构

Question

我有两个 mysql 转储文件。

dump1.sql

CREATE TABLE `designs` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `active` tinyint(1) NOT NULL,
  `template` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

dump2.sql

CREATE TABLE `designs` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `act` tinyint(1) NOT NULL,
      `temp` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
      PRIMARY KEY (`id`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

如何找出dump1和dump2中两个表结构的不同点？

Answer 1

第二个查询选择 table1 的所有 COLUMN_NAME 并通过使用 NOT IN 我们比较两个表的 COLUMN :-

SELECT COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_SCHEMA = 'your_schema' AND 
      TABLE_NAME = 'table2' AND 
      COLUMN_NAME NOT IN (
         SELECT COLUMN_NAME
         FROM INFORMATION_SCHEMA.COLUMNS 
         WHERE TABLE_SCHEMA = 'your_schema' AND 
               TABLE_NAME = 'table1');