我有如下所示的三个表:
Employee
+---------------+-------------+--------+
| employee_name | street | city |
+---------------+-------------+--------+
| abhishek | viman nagar | pune |
| neha | lohegaon | pune |
| prasahnt | viman nagar | pune |
| rahul | viman nagar | pune |
| rahul singh | lohegaon | mumbai |
+---------------+-------------+--------+
Works
+---------------+------------------+--------+
| employee_name | company_name | salary |
+---------------+------------------+--------+
| prasahnt | First Bank Corp | 90000 |
| rahul | First Bank Corp | 85000 |
| abhishek | First Bank Corp | 95000 |
| rahul singh | Second Bank Corp | 45000 |
| neha | Second Bank Corp | 65000 |
+---------------+------------------+--------+
Company
+------------------+--------+
| company_name | city |
+------------------+--------+
| First Bank Corp | pune |
| Second Bank Corp | mumbai |
+------------------+--------+
我想获取所有与他们工作的公司所在城市相同的employee_name。我该怎么做。
最佳答案
应该可以使用 JOIN 和 WHERE 来做到这一点，如下所示:
SELECT *
FROM Employee e
JOIN Works w ON w.employee_name = e.employee_name
JOIN Company c ON c.company_name = w.company_name
WHERE c.city = e.city
关于mysql - mysql中如何比较三个表的值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40140576/