php - 如何将逗号分隔的字符串与另一个逗号分隔的字符串匹配

Question

我想在mysql中匹配 2个逗号分隔的字符串，

测试字符串 => 家政、清洁、其他。

|              skills                 |
+-------------------------------------+
|    Housekeeping,Cleaning,Sweeping   |
+-------------------------------------+
|  Housewives,Beautician,Cleaning     |        AGAINST  `Housekeeping,Cleaning,Other`
+-------------------------------------+
|        PHP,Laravel,Other            |
+-------------------------------------+
|   Housekeeping,housekeeping,other   |
+-------------------------------------+


MUST MATCH  =>  All the `rows`

我听说过 LOCATE 语法，但不知道如何使用。

SELECT * FROM jobs_posted_by_employer WHERE skills [don't know]

我已将我的表在线用于查询执行!!!

这是我的查询:http://sqlfiddle.com/#!9/b1931

Answer 1

使用正则表达式(您需要使用 PHP 重新格式化您的输入):http://sqlfiddle.com/#!9/b1931/13

select
    *
from
    jobs_posted_by_employer
where
    skills regexp '(^|,)Housekeeping|Cleaning|Other(,|$)'

或者没有 PHP 重新格式化:http://sqlfiddle.com/#!9/b1931/40

select
    *
from
    jobs_posted_by_employer
where
    skills  regexp concat(
        '(^|,)',
        replace('Housekeeping,Cleaning,Other',',','|'),
        '(,|$)'
    )