Python 嵌套 For 循环向后计数

Question

这可能是一个简单的问题，但我试图创建一个嵌套循环，在外循环中从 0 计数到 9，在内循环中，从值(或索引)开始。它们是相同的在这种情况下)外循环并向后计数。

这是一个例子:

i= 0
k= 0

i= 1
k= 1
k= 0 

i= 2
k= 2
k= 1
k= 0

i= 3
k= 3
k= 2
k= 1
k= 0

我到目前为止:

x = range(0,10)
for i in x:
    print 'i = ',x[i]
    for k in x:
        print 'k = ', x[i::-1]

显然，上面的代码并没有达到我想要的效果。其一，第二个 for 循环不是从外循环中 i 的值开始而是向后计数。另一方面，它不会为每个新值打印新的 k =。

Answer 1

我认为应该是这样的:

x = range(0,10)
for i in x:
    print 'i = ',x[i]      
    for k in x[i::-1]:
        print 'k = ', k
    print("\n")

结果是:

i =  0
k =  0


i =  1
k =  1
k =  0


i =  2
k =  2
k =  1
k =  0


i =  3
k =  3
k =  2
k =  1
k =  0


i =  4
k =  4
k =  3
k =  2
k =  1
k =  0


i =  5
k =  5
k =  4
k =  3
k =  2
k =  1
k =  0


i =  6
k =  6
k =  5
k =  4
k =  3
k =  2
k =  1
k =  0


i =  7
k =  7
k =  6
k =  5
k =  4
k =  3
k =  2
k =  1
k =  0


i =  8
k =  8
k =  7
k =  6
k =  5
k =  4
k =  3
k =  2
k =  1
k =  0


i =  9
k =  9
k =  8
k =  7
k =  6
k =  5
k =  4
k =  3
k =  2
k =  1
k =  0

基本上，x[i::-1] 应该在 for 中而不是在 print 中。