python - 将字典 <str, list> 展平为综合列表

Question

所以我从服务器请求中得到了以下字典:

dict = {"first": "Mark", "last": "Zuckerberg", "alternative": ["Zuck", "Facebook guy"]}

我希望将其转换成这样的列表:

result = ["Mark", "Zuckerberg", "Zuck", "Facebook guy"]

我想我真的是为了个人的满足而努力让它保持 Python 风格。我去过的最接近的是这个，你可以告诉我它只给我嵌套列表而不是我真正要找的东西。

values = list(dict.values())
result = [item for sublist in values for item in sublist if isinstance(sublist, list)]

感谢任何输入。

Answer 1

你可以这样做:

def flatten(s):
    for e in s:
        if isinstance(e, (tuple, list)):
            yield from flatten(e)
        else:
            yield e


d = {"first": "Mark", "last": "Zuckerberg", "alternative": ["Zuck", "Facebook guy"]}

result = list(flatten(d.values()))

print(result)

输出

['Mark', 'Zuckerberg', 'Zuck', 'Facebook guy']

flatten 函数将处理任意嵌套列表。