c# - 使用 Task.WaitAll() 来处理等待的任务？

Question

理想情况下我想做的是用非阻塞模式延迟一个任务，然后等待所有任务完成。我试图添加 Task.Delay 返回的任务对象，然后使用 Task.WaitAll 但这似乎无济于事。我该如何解决这个问题？

class Program
{
    public static async void Foo(int num)
    {
        Console.WriteLine("Thread {0} - Start {1}", Thread.CurrentThread.ManagedThreadId, num);

        var newTask = Task.Delay(1000);
        TaskList.Add(newTask);
        await newTask;

        Console.WriteLine("Thread {0} - End {1}", Thread.CurrentThread.ManagedThreadId, num);
    }

    public static List<Task> TaskList = new List<Task>();

    public static void Main(string[] args)
    {
        for (int i = 0; i < 3; i++)
        {
            int idx = i;
            TaskList.Add(Task.Factory.StartNew(() => Foo(idx)));
        }

        Task.WaitAll(TaskList.ToArray());
    }
}

Answer 1

这就是您要实现的目标吗？

using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;

namespace ConsoleApplication
{
    class Program
    {
        public static async Task Foo(int num)
        {
            Console.WriteLine("Thread {0} - Start {1}", Thread.CurrentThread.ManagedThreadId, num);

            await Task.Delay(1000);

            Console.WriteLine("Thread {0} - End {1}", Thread.CurrentThread.ManagedThreadId, num);
        }

        public static List<Task> TaskList = new List<Task>();

        public static void Main(string[] args)
        {
            for (int i = 0; i < 3; i++)
            {
                int idx = i;
                TaskList.Add(Foo(idx));
            }

            Task.WaitAll(TaskList.ToArray());
            Console.WriteLine("Press Enter to exit...");
            Console.ReadLine();
        }
    }
}

输出:

Thread 10 - Start 0
Thread 10 - Start 1
Thread 10 - Start 2
Thread 6 - End 0
Thread 6 - End 2
Thread 6 - End 1
Press Enter to exit...