php - 以一种形式从具有相同名称的多个多选下拉列表中检索数据

Question

我正在尝试在一个页面和一个表单上处理多个具有相同名称的多选框/下拉列表。它们具有相同的名称，因为这些下拉菜单/框是动态添加的。我的问题是如何单独检索每个选择框的数据。它显示的结果是这样的:

Array(
        [0] => M
        [1] => T
        [2] => W 
 )

但我想要这样的结果

  Array
  (
     [0] => Array(
               [0] => M
               [2] => T
             )
     [1] => Array(
               [0] => W
             )
  )

我正在尝试这段代码:

  <td class="v-align-middle semi-bold sorting_1">
                            <div class="form-group form-group-default form-group-default-select2 full-width days" id="111">
                                    <label>SELECT DAYS</label>
                                    <select id="dw" name="days[]" class="full-width select2-offscreen" data-init-plugin="select2" multiple="" tabindex="-1">
                                        <option value="M">Monday</option>
                                        <option value="T">Tuesday</option>
                                        <option value="W">Wednesday</option>
                                        <option value="Th">Thursday</option>
                                        <option value="F">Friday</option>
                                        <option value="Sa">Saturday</option>
                                        <option value="Su">Sunday</option>
                                    </select>

                            </div> <br/>
                        </td>
                        <td>

这是我用来克隆我的表的代码:

   $('.add-ins').on('click', function(){
     var selfId = $(this).attr('id');
     var tId = $(this).parent().parent().find('table').attr('id');
     var lastId = $('.timings#'+tId+' tbody tr:visible:last').attr('id');
     lastId++;
     $('select').select2('destroy'); /* destroy select2 from select tag and then clone it */          
    var clonerow = $('.timings#'+tId+' tbody tr:visible:last').clone(true, true).attr('id', lastId);
    clonerow.appendTo('.timings#'+tId+' tbody');
    $('select').select2(); /* enable Select2 on the select elements */
});

PHP 代码:

  $days = $_POST['days'];
  foreach($days as $value){
       echo $value; 
       foreach($value as $week){ 
     echo  $week; 
     }
  }

或者只是这样:

   print_r($days);

请在这方面帮助我。如果有任何其他解决方案，例如为每个选择框使用不同的名称，请告诉我如何使用 php $_POST 发布它们，因为我不知道用户将添加多少个多选框。

我们将不胜感激您的建议。提前致谢。

亲切的问候

Answer 1

请像这样在html中编码

<select id="dw" name="days[0][]" class="full-width select2-offscreen" data-init-plugin="select2" multiple="" tabindex="-1">
 <option value="M">Monday</option>
 <option value="T">Tuesday</option>
 <option value="W">Wednesday</option>
 <option value="Th">Thursday</option>
 <option value="F">Friday</option>
 <option value="Sa">Saturday</option>
 <option value="Su">Sunday</option>
</select>

<select id="dw" name="days[1][]" class="full-width select2-offscreen" data-init-plugin="select2" multiple="" tabindex="-1">
 <option value="M">Monday</option>
 <option value="T">Tuesday</option>
 <option value="W">Wednesday</option>
 <option value="Th">Thursday</option>
 <option value="F">Friday</option>
 <option value="Sa">Saturday</option>
 <option value="Su">Sunday</option>
</select>