python - 从 python 程序发送邮件

Question

在下面的代码中，来自系统的邮件将进入用户的垃圾邮件文件夹，下面给出了 python 代码。我怀疑发件人来自 root@。 如何纠正这个问题

  def sendmail(to,fr,subject,msg):
     sendmail_location = "/usr/sbin/sendmail" # sendmail location
     p = os.popen("%s -t" % sendmail_location, "w")
     p.write("From: %s\n" % fr)
     p.write("Reply-to: %s\n" % fr)
     p.write("To: %s\n" % to)
     p.write("Content-type: text/html\n")
     p.write("Subject: %s\n" % subject)
     p.write("\n") # blank line separating headers from body
     p.write(msg)
     status = p.close()

接收到的邮件格式

     Delivered-To: harry@8767@gmail.com
     Received: by 19.143.162.8 with SMTP id k6gm828f7tfe;
             Tue, 19 Apr 2011 22:42:17 -0700 (PDT)
     Received: by 10.68.9.168 with SMTP id a5try030f516pbb.481.1303278137028;
             Tue, 19 Apr 2011 22:42:17 -0700 (PDT)
     Return-Path: <root@.>
     Received: from  ([174.1.161.204])
             by mx.google.com with ESMTPS id v4si18etrt0pbr.108.2011.04.19.22.42.15
             (version=TLSv1/SSLv3 cipher=OTHER);
             Tue, 19 Apr 2011 22:42:15 -0700 (PDT)
     Received-SPF: neutral (google.com: 74.3.161.204 is neither permitted nor denied by best guess record for domain of root@.) client-ip=74.3.161.204;
     Authentication-Results: mx.google.com; spf=neutral (google.com: 174.1.161.204 is neither permitted nor denied by best guess record for domain of root@.) smtp.mail=root@.
     Received: (qmail 23122 invoked by uid 0); 19 Apr 2011 22:36:27 -0000
     Date: 19 Apr 2011 22:36:27 -0000
     Message-ID: <2010041954235627.25121.qmail@>
     From: admin@xxxxxx.com
     Subject: hi

Answer 1

为什么直接使用sendmail二进制文件？？？

Python 有一个很好的 smtplib 模块，用于通过任意邮件服务器发送邮件 和一个电子邮件模块，用于编写符合 RFC-822 规范的邮件。

不太可能推荐您正在做的事情。