<分区>
程序:
#include <stdio.h>
int main() {
char t;
while(1) {
t='\0';
printf("\nExit?(y/n): ");
scanf("%c", &t);
if( t=='y' || t=='Y') {
return 0;
}
else
printf("\nContinuing...");
}
return 0;
}
输出:
$ vim Return.c
$ gcc -o Return Return.c
$ ./Return
Exit?(y/n): n
Continuing...
Exit?(y/n):
Continuing...
Exit?(y/n): n
Continuing...
Exit?(y/n):
Continuing...
Exit?(y/n): y
$
在将 'n' 作为输入后，
Continuing...
Exit?(y/n):
再循环一次，不接受用户的输入。如果代码有任何错误，请告诉我