python - 包含字典列表的字典

Question

这里是新手，对于重复/愚蠢的问题深表歉意，但我找不到答案。

我正在尝试将(字典)列表的内容存储到新字典中。

a={}
b=[]
c={"Name":"Claude","Surname":"Verde","Age":"35","City":"Paris"}
b.append(c)
c={"Name":"Jean","Surname":"Claude","Age":"22","City":"Paris"}
b.append(c)
c={"Name":"Sam","Surname":"Smith","Age":"42","City":"London"}
b.append(c)
c={"Name":"James","Surname":"Jones","Age":"44","City":"London"}
b.append(c)
for i in range(len(b)):
    if b[i]['City'] == 'Paris':
        a["Paris"]=([b[i]])
    elif b[i]['City'] == 'London':
        a["London"]=([b[i]])
a

结果:

{'Paris': [{'Name': 'Jean',
   'Surname': 'Claude',
   'Age': '22',
   'City': 'Paris'}],
 'London': [{'Name': 'James',
   'Surname': 'Jones',
   'Age': '44',
   'City': 'London'}]}

但是，我想要一个包含一个城市所有居民的字典。

上面的代码只存储列表中的第二个，而不是第一个。

即希望得到以下输出。

我怎样才能做到这一点？

非常感谢任何帮助。谢谢

{'Paris': [{'Name': 'Claude',
   'Surname': 'Verde',
   'Age': '35',
   'City': 'Paris'},{'Name': 'Jean',
   'Surname': 'Claude',
   'Age': '22',
   'City': 'Paris'}],
 'London': [{'Name': 'Sam',
   'Surname': 'Smith,
   'Age': '42',
   'City': 'London'},{'Name': 'James',
   'Surname': 'Jones',
   'Age': '44',
   'City': 'London'}]}

Answer 1

当你初始化 a 时，我会这样处理它:

a = {}

b=[]
c={"Name":"Claude","Surname":"Verde","Age":"35","City":"Paris"}
b.append(c)
c={"Name":"Jean","Surname":"Claude","Age":"22","City":"Paris"}
b.append(c)
c={"Name":"Sam","Surname":"Smith","Age":"42","City":"London"}
b.append(c)
c={"Name":"James","Surname":"Jones","Age":"44","City":"London"}
b.append(c)

for i in range(len(b)):
    if b[i]['City'] not in a.keys():
        a[b[i]['City']] = []

for i in range(len(b)):
    a[b[i]['City']].append(b[i]])

注意事项: 我很确定您可以像这样组合这些 for 循环:

for i in range(len(b)):
    if b[i]['City'] not in a.keys():
        a[b[i]['City']] = []
    a[b[i]['City']].append(b[i]])