我想了解如何在 C++ 中创建和处理一个无符号字符数组。如:
Array[0] = { new array of unsigned chars }
Array[1] = { new array of unsigned chars }
Array[2] = { new array of unsigned chars }
....and so on
我已经编写了下一个代码,但我感觉我做错了什么。代码工作正常,但我不知道我声明“缓冲区”的方式和我删除缓存的方式是否正确,或者是否会产生内存泄漏。
#define MAX_BUFFER 10
unsigned char* cache[MAX_BUFFER];
bool cache_full = false;
void AddToCache(unsigned char *buffer, const size_t buffer_size)
{
if (cache_full == true)
{
return;
}
for (int index = 0; index < MAX_BUFFER; index++)
{
if (cache[index] == NULL)
{
cache[index] = new unsigned char[buffer_size];
memcpy(cache[index], buffer, buffer_size);
}
if (index < MAX_BUFFER - 1)
{
cache_full = true;
}
}
}
void ClearCache()
{
for (int index = 0; index < MAX_BUFFER; index++)
{
if (cache[index] != NULL)
{
delete[] cache[index];
cache[index] = NULL;
}
}
cache_full = false;
}
bool IsCacheFull()
{
return cache_full;
}
最佳答案
这有用吗?
memcpy(cache, buffer, buffer_size);
不应该。这就是用 buffer
的内容覆盖 cache
中的所有指针。在上下文中,这可能应该是:
memcpy(cache[index], buffer, buffer_size);
此外,每次添加到缓存时,您都会将 cache_full
重复设置为 true
。尝试:
AddToCache(unsigned char *buffer, const size_t buffer_size)
{
for (int index = 0; index < MAX_BUFFER; index++)
{
if (cache[index] == NULL)
{
cache[index] = new unsigned char[buffer_size];
memcpy(cache[index], buffer, buffer_size);
return(index); // in case you want to find it again
}
}
// if we get here, we didn't find an empty space
cache_full = true;
return -1;
}
关于无符号字符数组的 C++ 数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21651739/