c++ - 如何在字符串中以圆周运动移动单词？

Question

我有一个包含 X 个单词的字符串(每个单词之间有一个空格)我必须根据用户插入的数字向左移动单词。例如:

“嗨，我叫 aviv，”，

用户输入了2。 “name is aviv and hi my”我正在寻找重复的合法性，但我找不到。

感谢指导。最重要的是，我不能使用内置库

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更新: 我看到有库的例子，我不能使用任何库。 所以我到目前为止所做的。 我写了一个函数，从用户那里获取一个字符串和一个数字，向左移动。 在将字符串发送到函数之前，我尝试计算需要移动的字符数。

我的输出是 - “name is avivhi my” 关于功能: 当它得到一个没有空格的字符串时，效果很好。

这是我的代码:

int main()
{
    char str[] = "hi my name is aviv";
    char str2[] = "hi my name is aviv";
    int CountSpace = 0, CountWord = 0;
    int Size = 18, flag = 0;
    int MoveLeft, Index = 0;
    for (int i = 0; str[i] != '\0'; i++)
    {
        if (str[i] == ' ')
        {
            CountSpace++;
        }    
    }

    CountWord = CountSpace + 1;//Understand how many words there are in a string.
    cin >> MoveLeft;

    if (MoveLeft >= CountWord)//
    {
        MoveLeft = (MoveLeft - ((MoveLeft / CountWord) * CountWord));//the size of movment;//To reduce the amount of moves if there is such a possibility
    }

    for (int i = Size - 1; i >= 0; i--)
    {
        if (str[i] == ' ')
        {
            flag++;
        }
        if (flag == MoveLeft)
        {
            Index = Size - 1 - (i + 1);//That's the amount of characters I have to move    
            break;
        }
    }    
    MoveLeft = Index;
    //This code belongs to the function that accepts a string and the amount to move the characters
    for (int i = 0; i < Size; i++)
    {
        if (i + MoveLeft < Size)
        {
            str[i] = str2[i + MoveLeft];
        }
        else
        {
            str[i] = str2[(i + MoveLeft) - Size];
        }
    }
    cout << "Move Left: " << MoveLeft << endl << str << endl << str2 << endl;
    return 0;
}

Answer 1

这里有一个提示:

vector<string> words = Your_Code_To_Split_Input_Into_Words();
int count = words.size();
int shift = Your_Code_To_Read_Users_Input();

// print the sentence with the rotation specified by shift
for (int i = 0; i < count; i++)
{
    int shifted_index = (i + shift) % count;  // modulo math implements circular rotation
    string spacing = (i == 0) ? "" : " ";     // add a space before each word, except first word
    cout << spacing << words[shifted_index];
}
cout << endl;