我正在尝试从 web site 中检索一些数据.
我写了一个 java 类,它似乎适用于许多网站,但它不适用于这个特定的网站,它在输入表单中使用了大量的 javascript。
正如您从代码中看到的那样,我指定了从 HTML 源中获取名称的输入字段,但也许这个网站不接受这种 POST 请求?
如何模拟用户交互来检索生成的 HTML?
package com.transport.urlRetriver;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
public class UrlRetriver {
String stationPoller (String url, ArrayList<NameValuePair> params) {
HttpPost postRequest;
HttpResponse response;
HttpEntity entity;
String result = null;
DefaultHttpClient httpClient = new DefaultHttpClient();
try {
postRequest = new HttpPost(url);
postRequest.setEntity((HttpEntity) new UrlEncodedFormEntity(params));
response = httpClient.execute(postRequest);
entity = response.getEntity();
if(entity != null){
InputStream inputStream = entity.getContent();
result = convertStreamToString(inputStream);
}
} catch (Exception e) {
result = "We had a problem";
} finally {
httpClient.getConnectionManager().shutdown();
}
return result;
}
void ATMtravelPoller () {
ArrayList<NameValuePair> params = new ArrayList<NameValuePair>(2);
String url = "http://www.atm-mi.it/it/Pagine/default.aspx";
params.add(new BasicNameValuePair("ctl00$SPWebPartManager1$g_afa5adbb_5b60_4e50_8da2_212a1d36e49c$txt_address_s", "Viale romagna 1"));
params.add(new BasicNameValuePair("ctl00$SPWebPartManager1$g_afa5adbb_5b60_4e50_8da2_212a1d36e49c$txt_address_e", "Viale Toscana 20"));
params.add(new BasicNameValuePair("sf_method", "POST"));
String result = stationPoller(url, params);
saveToFile(result, "/home/rachele/Documents/atm/out4.html");
}
static void saveToFile(String toFile, String pos){
try{
// Create file
FileWriter fstream = new FileWriter(pos);
BufferedWriter out = new BufferedWriter(fstream);
out.write(toFile);
//Close the output stream
out.close();
}catch (Exception e){//Catch exception if any
System.err.println("Error: " + e.getMessage());
}
}
private static String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder stringBuilder = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
stringBuilder.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return stringBuilder.toString();
}
}
最佳答案
在我看来,可能存在具有动态值的 javascript 生成字段,以防止自动代码抓取网站。发送您要下载的具体站点。
关于java - 带有问题网站的 HTTP 客户端 POST,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4775585/