我正在尝试使用以下代码在 Angularjs 中编写待办事项应用程序。
function write_controller($scope){
$scope.todos = [{text:'hey all',done:false},
{text:'hello',done:false}];
$scope.addtodo = function(){
$scope.todos.push({text:$scope.todopush,done:false});
$scope.todopush = '';
}
$scope.delete = function(){
var oldtodos = $scope.todos;
$scope.todos = [];
angular.forEach(oldtodos, function(x){
if (!x.done){
$scope.todos.push(x);}
});
};
}<html ng-app>
<head>
<script src =
"https://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js">
</script>
</head>
<body>
<div class = "basic_class" ng-controller = "write_controller">
<ul>
<li ng-repeat = "todo in todos"><input type = "checkbox" ng-model
="todo.done">{{todo.text}}</input></li>
</ul>
<input type = "text"
placeholder = "please add data here"
ng-model="todopush">
</input>
<input type = "button" ng-click ="addtodo()" value ="Click me!!"></input>
<input type = "button" ng-click = "delete()" ng-model="remove" value =
"remove!"></input>
</div>
</body>
</html>在下面的代码中，我有以下问题。 删除操作是如何工作的？？
我的理解: 1)它将现有数组插入一个新数组 2)清除现有数组 3)遍历新数组 3)检查完成的功能？？？ (当它说 !x.done 时，它是真还是假？？？) 任何帮助将不胜感激。
最佳答案
完成步骤
$scope.delete = function() {
// store existing todos array in variable
var oldtodos = $scope.todos;
// create new empty array for todos
$scope.todos = [];
// loop over previously stored todos
angular.forEach(oldtodos, function(x) {//x is element of the array - a single todo object
// if x.done is not truthy
if (!x.done){
// push this item into `$scope.todos`
$scope.todos.push(x);
});
}
基本上它只会将 done:false 推送到新版本的 $scope.todos 中，从而有效地删除 done:true
关于javascript - 在 AngularJS 中编写待办事项列表时无法理解删除过程，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39939751/