我正在尝试编写代码,将 10 序列 DNA 片段与亲属的 10 序列 DNA 片段进行比较。用户输入他们的姓名、他们想要比较的亲属数量以及他们的 DNA。计算机输出匹配的百分比。与 ATAAGACGCA 相比,ATTAGACGCA 将匹配 90%。在用户声明有多少亲戚后,亲戚的数量是一个常数。我试过使用const,但它似乎不想使用数字。
/**********************************************************************
* Get DNA Sequence
***********************************************************************/
void getMyDNA(char myDNA[])
{
cout << "Enter your DNA sequence: ";
cin >> myDNA;
}
/**********************************************************************
* Get Potential Relatives
***********************************************************************/
int getRelatives()
{
int relatives = 0;
cout << "Enter the number of potential relatives: ";
cin >> relatives;
return relatives;
}
/**********************************************************************
* Get Potential Relatives Names
***********************************************************************/
void getRelativeName(string relativeNames[], int relatives)
{
string name;
for (int i = 0; i < relatives; i++)
{
cout << "Please enter the name of relative #" << i + 1 << ": ";
cin >> name;
relativeNames[i] = name;
}
}
/**********************************************************************
* Get Potential Relatives DNA Sequence
***********************************************************************/
void getRelativeDNA(char relativeDNA[][10], string relativeNames[], int relatives)
{
for (int i = 0; i < relatives; i++)
{
cout << "Please enter the DNA sequence for " << relativeNames[i] << ": ";
cin >> relativeDNA[i];
}
}
/**********************************************************************
* Display Potential Relatives Match
***********************************************************************/
void displayMatch(string relativeNames, char relativeDNA[][10], int relatives, char myDNA[])
{
const int family = relatives;
int count[family] = 0;
for (int r = 0; r < 3; r++) //relative number r
{
for (int d = 0; d < 10; d++) //dna piece number d
{
if (relativeDNA[r][d] == myDNA[d])
count[r]++;
}
}
}
/**********************************************************************
* Main
***********************************************************************/
int main()
{
char myDNA[10];
string relativeNames[50];
char relativeDNA[50][10];
// My DNA
getMyDNA(myDNA);
//# of relatives
int relatives = getRelatives();
cout << endl;
//thier names
getRelativeName(relativeNames,relatives);
cout << endl;
//their dna
getRelativeDNA(relativeDNA,relativeNames,relatives);
cout << endl;
//display
displayMatch(relativeNames,relativeDNA,relatives,myDNA);
return 0;
}
最佳答案
代替
int count[relatives] = 0;
当 relatives
时作为标准 C++ 是无效的可以在运行时变化,使用
std::vector<int> count( relatives );
包括 <vector>
标题。
关于c++ - 在 C++ 中使用变量作为数组参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36805905/