sql - 在 MariaDB 中搜索子字符串或单词

Question

我尝试在 MariaDB 上进行全文搜索，但遇到了无法处理的问题。

我的表生成为;

CREATE TABLE test (email TEXT, FULLTEXT(email)) ENGINE=InnoDB;

然后插入一些数据；

MariaDB [frauctive]> select * from test;
+---------------------------------+
| email                           |
+---------------------------------+
| david@hotmail.com               |
| michael@gmail.com               |
| christian@gmail.com             |
| david01@hotmail.com             |
| davidblatt@hotmail.com          |
| beckhamdavidbeckham@hotmail.com |
+---------------------------------+

当我使用 match against 函数时，我无法检索到我想要获得的相似度分数；

MariaDB [frauctive]> SELECT email, MATCH(email) AGAINST('*david*' IN         BOOLEAN MODE) AS relevance 
->   FROM test ORDER BY relevance DESC;
+---------------------------------+--------------------+
| email                           | relevance          |
+---------------------------------+--------------------+
| david@hotmail.com               | 0.0906190574169159 |
| david01@hotmail.com             | 0.0906190574169159 |
| davidblatt@hotmail.com          | 0.0906190574169159 |
| michael@gmail.com               |                  0 |
| christian@gmail.com             |                  0 |
| beckhamdavidbeckham@hotmail.com |                  0 |
+---------------------------------+--------------------+

虽然“beckhamdavidbeckham@hotmail.com”条目包含“david”模式，但分数返回 0。

你能帮我解决这个相关问题吗？

Answer 1

关于 * 通配符:

通配符，表示零个或多个字符。它只能出现在单词的末尾。

来源: https://mariadb.com/kb/en/mariadb/fulltext-index-overview/

请尝试:

MariaDB [frauctive]> SELECT email, MATCH(email) AGAINST('david*' IN         BOOLEAN MODE) AS relevance 
->   FROM test ORDER BY relevance DESC;

或者

MariaDB [frauctive]> SELECT email, MATCH(email) AGAINST('david' IN         BOOLEAN MODE) AS relevance 
->   FROM test ORDER BY relevance DESC;