c - 如何替换char *中的char

Question

这里是新手。 我试图替换 char * 中的一个字符，但我的程序出错

#include <stdio.h>

int main(int argc, char **argv)
{
    char *mystring ="love is alweys better yoe";
    int count = 1;

    for (count ;  count < 23; count++)
    {     
    if ((mystring[count] == 0x65 )) //&& ((mystring[count+1] > 0x41) && (mystring[count+1] < 0x7A))) 
    {
      mystring[count] = 0x45; //here occur the freezing
      printf ("%c\n", mystring[count]); 
      //break;
    };
    };

    printf("%s\n",mystring);
    return 0;
}

Answer 1

char *mystring ="love is alweys better yoe"

将 mystring 设为只读

你需要先将字符串复制到缓冲区中才能更改它

例如

char mystring[128];
strcpy( mystring , "love is alweys better yoe" );