python - 具有多个断点的可拖动线

标签 python drag-and-drop pyqt pyqt4 pyqtgraph

我有一个与以下问题非常相似的应用程序:Draw half infinite lines?

我想要一条具有多个阈值的无限线。

enter image description here

问题中提供的解决方案是一个很好的起点:https://stackoverflow.com/a/37836348/7163293

我试图通过修改 __init__ 中的 movable 属性来使线条可移动,并添加一个 setMovable 方法,就像源代码中的源代码一样:

http://www.pyqtgraph.org/documentation/_modules/pyqtgraph/graphicsItems/InfiniteLine.html#InfiniteLine

from pyqtgraph.Qt import QtGui
import numpy as np
import pyqtgraph as pg

class InfiniteLineWithBreak(pg.GraphicsObject):

    def __init__(self, changeX, levelsY, pen=None):
        pg.GraphicsObject.__init__(self)

        self.changeX = changeX
        self.levelsY = levelsY

        self.maxRange = [None, None]
        self.moving = False
        self.movable = True
        self.setMovable(self.movable)
        self.mouseHovering = False

        pen = (200, 200, 100)
        self.setPen(pen)
        self.setHoverPen(color=(255,0,0), width=self.pen.width())
        self.currentPen = self.pen

    def setMovable(self, m):
        """Set whether the line is movable by the user."""
        self.movable = m
        self.setAcceptHoverEvents(m)


    def setBounds(self, bounds):
        self.maxRange = bounds
        self.setValue(self.value())

    def setPen(self, *args, **kwargs):
        self.pen = pg.fn.mkPen(*args, **kwargs)
        if not self.mouseHovering:
            self.currentPen = self.pen
            self.update()

    def setHoverPen(self, *args, **kwargs):
        self.hoverPen = pg.fn.mkPen(*args, **kwargs)
        if self.mouseHovering:
            self.currentPen = self.hoverPen
            self.update()

    def boundingRect(self):
        br = self.viewRect()
        return br.normalized()

    def paint(self, p, *args):
        br = self.boundingRect()
        p.setPen(self.currentPen)
        # three lines (left border to change point, change point vertical, change point to right)
        p.drawLine(pg.Point(br.left(), self.levelsY[0]), pg.Point(self.changeX, self.levelsY[0]))
        p.drawLine(pg.Point(self.changeX, self.levelsY[0]), pg.Point(self.changeX, self.levelsY[1]))
        p.drawLine(pg.Point(self.changeX, self.levelsY[1]), pg.Point(br.right(), self.levelsY[1]))

    def dataBounds(self, axis, frac=1.0, orthoRange=None):
        if axis == 0:
            return None   ## x axis should never be auto-scaled
        else:
            return (0,0)

    def setMouseHover(self, hover):
        pass

app = QtGui.QApplication([])
w = pg.GraphicsWindow()
w.resize(1000, 600)
v = w.addPlot(y=np.random.normal(size=100))
v.addItem(InfiniteLineWithBreak(changeX=50, levelsY=(-1, 1)))
app.exec_()

然而,修改后这条线仍然不能移动。所以我有点卡在这里了。有人可以提供一些指示吗?

此外,理想情况下,应用程序上的线条应该可以分段移动。因此,当用户拖动一条线时,只有断点之间的部分在移动。所以理想情况下我想要这样的东西:

Draggable line with draggable points

在我的申请中。理想情况下它看起来像

enter image description here

阈值点级别 (TH_Px_L1) 可拖动但时间 (TH_Px_T1) 不可拖动,因此点只能垂直移动。

如果有人也可以在第二项上提供帮助并提供一些非常有帮助的指示或解决方案。

最佳答案

基于 this example来自文档。

散点图类似于绘制图形,但连接线位于第 i 个点和第 i + 1 个点之间。然后我们将移动限制在垂直轴上,因为这是作者的要求。

import numpy as np
import pyqtgraph as pg
from pyqtgraph.Qt import QtCore, QtGui

pg.setConfigOptions(antialias=True)

w = pg.GraphicsWindow()
w.setWindowTitle('Draggable')


class Graph(pg.GraphItem):
    def __init__(self):
        self.dragPoint = None
        self.dragOffset = None
        pg.GraphItem.__init__(self)

    def setData(self, **kwds):
        self.data = kwds
        if 'pos' in self.data:
            npts = self.data['pos'].shape[0]
            self.data['adj'] = np.column_stack((np.arange(0, npts-1), np.arange(1, npts)))
            self.data['data'] = np.empty(npts, dtype=[('index', int)])
            self.data['data']['index'] = np.arange(npts)
        self.updateGraph()

    def updateGraph(self):
        pg.GraphItem.setData(self, **self.data)

    def mouseDragEvent(self, ev):
        if ev.button() != QtCore.Qt.LeftButton:
            ev.ignore()
            return

        if ev.isStart():
            pos = ev.buttonDownPos()
            pts = self.scatter.pointsAt(pos)
            if len(pts) == 0:
                ev.ignore()
                return
            self.dragPoint = pts[0]
            ind = pts[0].data()[0]
            self.dragOffset = self.data['pos'][ind][1] - pos[1]
        elif ev.isFinish():
            self.dragPoint = None
            return
        else:
            if self.dragPoint is None:
                ev.ignore()
                return

        ind = self.dragPoint.data()[0]
        self.data['pos'][ind][1] = ev.pos()[1] + self.dragOffset
        self.updateGraph()
        ev.accept()


g = Graph()
v = w.addPlot()
v.addItem(g)

x = np.linspace(1, 100, 40)
pos = np.column_stack((x, np.sin(x)))

g.setData(pos=pos, size=10, pxMode=True)

if __name__ == '__main__':
    import sys

    if (sys.flags.interactive != 1) or not hasattr(QtCore, 'PYQT_VERSION'):
        QtGui.QApplication.instance().exec_()

enter image description here

关于python - 具有多个断点的可拖动线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45624912/

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