我有一个与以下问题非常相似的应用程序:Draw half infinite lines?
我想要一条具有多个阈值的无限线。
问题中提供的解决方案是一个很好的起点:https://stackoverflow.com/a/37836348/7163293
我试图通过修改 __init__
中的 movable
属性来使线条可移动,并添加一个 setMovable
方法,就像源代码中的源代码一样:
from pyqtgraph.Qt import QtGui
import numpy as np
import pyqtgraph as pg
class InfiniteLineWithBreak(pg.GraphicsObject):
def __init__(self, changeX, levelsY, pen=None):
pg.GraphicsObject.__init__(self)
self.changeX = changeX
self.levelsY = levelsY
self.maxRange = [None, None]
self.moving = False
self.movable = True
self.setMovable(self.movable)
self.mouseHovering = False
pen = (200, 200, 100)
self.setPen(pen)
self.setHoverPen(color=(255,0,0), width=self.pen.width())
self.currentPen = self.pen
def setMovable(self, m):
"""Set whether the line is movable by the user."""
self.movable = m
self.setAcceptHoverEvents(m)
def setBounds(self, bounds):
self.maxRange = bounds
self.setValue(self.value())
def setPen(self, *args, **kwargs):
self.pen = pg.fn.mkPen(*args, **kwargs)
if not self.mouseHovering:
self.currentPen = self.pen
self.update()
def setHoverPen(self, *args, **kwargs):
self.hoverPen = pg.fn.mkPen(*args, **kwargs)
if self.mouseHovering:
self.currentPen = self.hoverPen
self.update()
def boundingRect(self):
br = self.viewRect()
return br.normalized()
def paint(self, p, *args):
br = self.boundingRect()
p.setPen(self.currentPen)
# three lines (left border to change point, change point vertical, change point to right)
p.drawLine(pg.Point(br.left(), self.levelsY[0]), pg.Point(self.changeX, self.levelsY[0]))
p.drawLine(pg.Point(self.changeX, self.levelsY[0]), pg.Point(self.changeX, self.levelsY[1]))
p.drawLine(pg.Point(self.changeX, self.levelsY[1]), pg.Point(br.right(), self.levelsY[1]))
def dataBounds(self, axis, frac=1.0, orthoRange=None):
if axis == 0:
return None ## x axis should never be auto-scaled
else:
return (0,0)
def setMouseHover(self, hover):
pass
app = QtGui.QApplication([])
w = pg.GraphicsWindow()
w.resize(1000, 600)
v = w.addPlot(y=np.random.normal(size=100))
v.addItem(InfiniteLineWithBreak(changeX=50, levelsY=(-1, 1)))
app.exec_()
然而,修改后这条线仍然不能移动。所以我有点卡在这里了。有人可以提供一些指示吗?
此外,理想情况下,应用程序上的线条应该可以分段移动。因此,当用户拖动一条线时,只有断点之间的部分在移动。所以理想情况下我想要这样的东西:
Draggable line with draggable points
在我的申请中。理想情况下它看起来像
阈值点级别 (TH_Px_L1) 可拖动但时间 (TH_Px_T1) 不可拖动,因此点只能垂直移动。
如果有人也可以在第二项上提供帮助并提供一些非常有帮助的指示或解决方案。
最佳答案
基于 this example来自文档。
散点图类似于绘制图形,但连接线位于第 i 个点和第 i + 1 个点之间。然后我们将移动限制在垂直轴上,因为这是作者的要求。
import numpy as np
import pyqtgraph as pg
from pyqtgraph.Qt import QtCore, QtGui
pg.setConfigOptions(antialias=True)
w = pg.GraphicsWindow()
w.setWindowTitle('Draggable')
class Graph(pg.GraphItem):
def __init__(self):
self.dragPoint = None
self.dragOffset = None
pg.GraphItem.__init__(self)
def setData(self, **kwds):
self.data = kwds
if 'pos' in self.data:
npts = self.data['pos'].shape[0]
self.data['adj'] = np.column_stack((np.arange(0, npts-1), np.arange(1, npts)))
self.data['data'] = np.empty(npts, dtype=[('index', int)])
self.data['data']['index'] = np.arange(npts)
self.updateGraph()
def updateGraph(self):
pg.GraphItem.setData(self, **self.data)
def mouseDragEvent(self, ev):
if ev.button() != QtCore.Qt.LeftButton:
ev.ignore()
return
if ev.isStart():
pos = ev.buttonDownPos()
pts = self.scatter.pointsAt(pos)
if len(pts) == 0:
ev.ignore()
return
self.dragPoint = pts[0]
ind = pts[0].data()[0]
self.dragOffset = self.data['pos'][ind][1] - pos[1]
elif ev.isFinish():
self.dragPoint = None
return
else:
if self.dragPoint is None:
ev.ignore()
return
ind = self.dragPoint.data()[0]
self.data['pos'][ind][1] = ev.pos()[1] + self.dragOffset
self.updateGraph()
ev.accept()
g = Graph()
v = w.addPlot()
v.addItem(g)
x = np.linspace(1, 100, 40)
pos = np.column_stack((x, np.sin(x)))
g.setData(pos=pos, size=10, pxMode=True)
if __name__ == '__main__':
import sys
if (sys.flags.interactive != 1) or not hasattr(QtCore, 'PYQT_VERSION'):
QtGui.QApplication.instance().exec_()
关于python - 具有多个断点的可拖动线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45624912/