c++ - 非静态数据成员的cppreference定义是否错误？

Question

来自 cppreference 的定义:

Non-static data members are the variables that are declared in a member specification of a class.

他们有例子:

class S
{
   int& r;               // non-static data member of reference type
};

但我们知道非静态数据成员引用不是变量，因为标准:

§3/6: A variable is introduced by the declaration of a reference other than a non-static data member or of an object.

那么他们对非静态数据成员的定义是否错误(他们忘记了这个异常)？在哪里可以找到术语“非静态数据成员”的正确定义？

很遗憾，我在 C++ 标准中找不到非静态数据成员的定义。

编辑:来自cppreference object definition和下面的讨论我们可以得出结论，非静态数据成员根本不是对象。和 cppreference non-static member page更正了目前讨论的定义。

Answer 1

So their definition of non-static data member is wrong

是的，在数据​​成员页面的介绍性句子中使用“变量”这个词是错误的(而且，正如评论中提到的，它是一个 wiki，wiki 页面上的讨论选项卡获得更快的反馈)。

当前的标准写法是 3[basic]/6 和:

A variable is introduced by the declaration of a reference other than a non-static data member or of an object. The variable’s name, if any, denotes the reference or object.

因此，引用数据成员被显式排除，要弄清楚其余部分，您需要 1.8[intro.object]/1

中的“对象”定义

An object is created by a definition (3.1), by a new-expression (5.3.4), when implicitly changing the active member of a union (9.3), or when a temporary object is created (4.4, 12.2).

最后 3.1[basic.def]/2

A declaration is a definition unless ... it declares a non-inline static data member in a class definition (9.2, 9.2.3),

虽然看起来变量和数据成员之间的区别是不切实际的语言律师主义，但在理解编译器诊断时它实际上很重要，至少在这种情况下:

struct X {
    int m;
    void f() { auto l = [m](){ return m; }; }
};

海湾合作委员会:

error: capture of non-variable 'X::m' 

clang :

error: 'm' in capture list does not name a variable

国际刑事法院:

error: member "X::m" is not a variable