<?xml version="1.0"?>
<AppXmlLogWritter>
<LogData>
<LogID>5678201301161640382919</LogID>
<LogDateTime>20130114164038</LogDateTime>
</LogData>
<LogData>
<LogID>5678201301161640382920</LogID>
<LogDateTime>20130115154040</LogDateTime>
</LogData>
<LogData>
<LogID>5678201301161640382921</LogID>
<LogDateTime>20130116164042</LogDateTime>
</LogData>
</AppXmlLogWritter>
为了删除我在 xpath 查询下使用的一个节点
string xpathQuery = "/AppXmlLogWritter/LogData[LogDateTime ='" + txtToDate.Text.Trim() + "']";
XmlNodeList objxmlNodeList = objXmldoc.SelectNodes(xpathQuery);
for (int i = 0; i <= objxmlNodeList.Count - 1; i++)
{
objxmlNodeList[i].ParentNode.RemoveChild(objxmlNodeList[i]);
lblMessage.Text = "Record deleted sucessfully.";
}
我在各种应用程序的 XML 文件中编写日志。用户可以在 LogDateTime 范围内删除日志的位置。我的 XPath 查询如何删除 LogDateTime 范围内的日志。
示例:如果我必须删除日期时间范围 20130116164038 到 20130116164040 之间的日志。
最佳答案
试试这个:
strXpathQuery = "/AppXmlLogWritter/LogData[LogDateTime >='" + txtFromDate.Text.Trim() + "' and LogDateTime <='" + txtToDate.Text.Trim() +"']";
要获取指定日期的所有日志数据,您可以使用此方法:
strXpathQuery = "/AppXmlLogWritter/LogData[starts-with(LogDateTime, '20130116')]";
要在 LogDateTime
范围从 '20130114' 到 '20130116' 时获取所有 logdata
你可以使用这个:
strXpathQuery = "/AppXmlLogWritter/LogData[substring(LogDateTime, 1, 8) >='20130114' and substring(LogDateTime, 1, 8) <='20130116']";
关于c# - 查询删除 logdatetime 范围内的日志,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14393761/