xml - XQuery - 分组和计数

Question

这是我的 XML 文件的结构 -

<A>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mr.">Allen Bond</Name>
  <Name t="Mr." p="X">James Bond</Name>
  <Name t="Mr." p="X">James Bond</Name>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mrs.">James Bond</Name>
  <Name t="Mrs.">James Bond</Name>
  <Name t="Mr.">James Bond</Name>
  <Name t="Mrs." p="Y">James Bond</Name>
  <Name t="Mrs." p="Y">James Bond</Name>
</A>

我期望的输出是 -

<A>
  <N>Allen Bond Mr - 1</N>
  <N>James Bond Mr - 3</N>
  <N>James Bond Mr, X - 2</N>
  <N>James Bond Mrs - 2</N>  
  <N>James Bond Mrs, Y - 2</N>
</A>

我能够获得不同的名称，但无法添加计数...

Answer 1

XQuery 3.0 解决方案 group by :

<A>{
  for $name in //Name
  let $full :=
    if(not($name/@p)) then concat($name, ' ', $name/@t)
    else concat($name, ' ', $name/@t, ', ', $name/@p)
  group by $full
  return <N>{$full, '-', count($name)}</N>
}</A>

XQuery 1.0 解决方案 distinct-values($arg) :

<A>{
  let $names :=
    for $name in //Name
    return if(not($name/@p)) then concat($name, ' ', $name/@t)
    else concat($name, ' ', $name/@t, ', ', $name/@p)
  for $name in distinct-values($names)
  return <N>{$name, '-', count($names[. eq $name])}</N>
}</A>