windows - 如何通过批量启用延迟扩展来逃避“

Question

编写一个简单的脚本来查找和替换批处理中的字符。我的脚本包含“我想用一些文本替换它的字符”。请告诉我哪个转义字符会有所帮助。试过“”和^”不行 脚本 : `

    @echo off &setlocal 
    set search2="""
    set "replace2=""
    set "textfile=D:\Users\manajosh\Desktop\try-Copy.xml"
    set "newfile=D:\Users\manajosh\Desktop\Output.txt"
    (for /f "delims=" %%i in (%textfile%) do (
        set "line=%%i"
        setlocal enabledelayedexpansion
            set "line=!line:%search2%=%replace2%!"
            echo(!line!
        endlocal
    ))>"%newfile%"

pause 6

`

Answer 1

试试这个技巧:

@echo off
set "search2=""
rem  set search2="""
set "replace2=""
set "line="quoted""
setlocal enableDelayedExpansion
 for /f "usebackq tokens=1,2 delims=§" %%a in ('"!search2!"§"!replace2!"') do echo "!line:%%~a=%%~b!"
endlocal

问题是您需要延迟扩展行以及 search2 和 replace2 - 这可以通过包装 for 循环来实现。