windows - Windows x64 的 44 位虚拟内存地址限制背后

Question

http://www.alex-ionescu.com/?p=50 。

我读了上面的帖子。作者以单链表为例解释了为什么Windows x64仅支持44位虚拟内存地址。

struct {  // 8-byte header
        ULONGLONG Depth:16;
        ULONGLONG Sequence:9;
        ULONGLONG NextEntry:39;
} Header8;

The first sacrifice to make was to reduce the space for the sequence number to 9 bits instead of 16 bits, reducing the maximum sequence number the list could achieve. This still only left 39 bits for the pointer — a mediocre improvement over 32 bits. By forcing the structure to be 16-byte aligned when allocated, 4 more bits could be won, since the bottom bits could now always be assumed to be 0.

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哦，我听不懂。

什么“通过在分配时强制结构进行 16 字节对齐，可以多赢得 4 位，因为现在可以始终假定底部位为 0。”方法？

Answer 1

16 is 0010000 in binary

32 is 0100000 in binary

64 is 1000000 in binary

等等

您可以看到，对于所有 16 的倍数的数字，最后四位始终为零。 因此，您可以将它们保留下来，并在需要使用指针时将它们添加回来，而不是存储这些位。