我正在尝试使用 C# 的 TPL 并行获取所有进程的 CPU%。我的代码是:
private IDictionary<Process, int> _usage = new Dictionary<Process, int>();
public ProcessCpuUsageGetter()
{
Process[] processes = Process.GetProcesses();
int processCount = processes.Count();
Task[] tasks = new Task[processCount];
int counter = 0;
for (int i = 0; i < processCount; i++)
{
tasks[i] = Task.Factory.StartNew(() => DoWork(processes[i]));
}
Task.WaitAll(tasks);
}
private void DoWork(object o)
{
Process process = (Process)o;
PerformanceCounter pc = new PerformanceCounter("Process", "% Processor Time", process.ProcessName, true);
pc.NextValue();
Thread.Sleep(1000);
int cpuPercent = (int)pc.NextValue() / Environment.ProcessorCount;
_usage.Add(process, cpuPercent);
}
但它失败了,已经添加了一个具有相同键的项目。
关于我做错了什么的任何想法?
最佳答案
问题是局部变量i
在传递给启动任务的表达式时关闭。这会导致 DoWork(processes[i])
使用 i 的当前值,即使 i
被 for
修改。
创建局部变量:
for (int i = 0; i < processCount; i++)
{
int localI = i;
tasks[i] = Task.Factory.StartNew(() => DoWork(processes[localI]));
}
关于c# - 并行获取所有进程,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5909776/