c# - 如何告诉继承类不要调用其基类的无参数构造函数？

Question

我惊讶地发现，每当我在派生类中调用 any 构造函数时，都会调用基类的无参数构造函数。我认为这就是 : base() 的用途，显式在需要时调用基本构造函数。

如何在实例化派生类时阻止调用基类构造函数？

using System;

namespace TestConstru22323
{
    class Program
    {
        static void Main(string[] args)
        {
            Customer customer = new Customer("Jim", "Smith");
            Customer c = new Customer();
            Console.WriteLine(customer.Display());

            Console.ReadLine();
        }
    }

    public class Person
    {
        public Person()
        {
            Console.WriteLine("I don't always want this constructor to be called. I want to call it explicitly.");
        }
    }

    public class Customer : Person
    {
        private string _firstName;
        private string _lastName;

        //public Customer(string firstName, string lastName): base()  //this explicitly calls base empty constructor
        public Customer(string firstName, string lastName) //but this calls it anyway, why?
        {
            _firstName = firstName;
            _lastName = lastName;
        }

        public string Display()
        {
            return String.Format("{0}, {1}", _lastName, _firstName);
        }
    }
}

Answer 1

唯一的方法是明确告诉它你希望它调用哪个other base ctor；这当然意味着您必须选择一些 base ctor 来调用。

您不能让它根本不调用任何基构造函数 - 概念上，构造一个 Customer通过首先构造一个 Person 来完成, 然后做 Customer其上的特定结构。例如，假设 Person有private字段 - 如果构造一个 Customer，这些将如何正确构造被允许不首先构造一个Person ？