python - 在 Django 中流式传输 CSV 文件

标签 python django csv streaming

我正在尝试将 csv 文件作为附件下载流式传输。 CSV 文件的大小将达到 4MB 或更大,我需要一种方法让用户主动下载文件,而无需等待所有数据被创建并首先提交到内存。

我首先使用了我自己的基于 Django 的 FileWrapper 类的文件包装器。那失败了。然后我在这里看到了一种使用生成器流式传输响应的方法: How to stream an HttpResponse with Django

当我在生成器中引发错误时,我可以看到我正在使用 get_row_data() 函数创建正确的数据,但是当我尝试返回响应时,它返回为空。我还禁用了 Django GZipMiddleware。有谁知道我做错了什么?

编辑:我遇到的问题是 ConditionalGetMiddleware。我不得不替换它,代码在下面的答案中。

这里是 View :

from django.views.decorators.http import condition

@condition(etag_func=None)
def csv_view(request, app_label, model_name):
    """ Based on the filters in the query, return a csv file for the given model """

    #Get the model
    model = models.get_model(app_label, model_name)

    #if there are filters in the query
    if request.method == 'GET':
        #if the query is not empty
        if request.META['QUERY_STRING'] != None:
            keyword_arg_dict = {}
            for key, value in request.GET.items():
                #get the query filters
                keyword_arg_dict[str(key)] = str(value)
            #generate a list of row objects, based on the filters
            objects_list = model.objects.filter(**keyword_arg_dict)
        else:
            #get all the model's objects
            objects_list = model.objects.all()
    else:
        #get all the model's objects
        objects_list = model.objects.all()
    #create the reponse object with a csv mimetype
    response = HttpResponse(
        stream_response_generator(model, objects_list),
        mimetype='text/plain',
        )
    response['Content-Disposition'] = "attachment; filename=foo.csv"
    return response

这是我用来流式传输响应的生成器:

def stream_response_generator(model, objects_list):
    """Streaming function to return data iteratively """
    for row_item in objects_list:
        yield get_row_data(model, row_item)
        time.sleep(1)

这是我创建 csv 行数据的方法:

def get_row_data(model, row):
    """Get a row of csv data from an object"""
    #Create a temporary csv handle
    csv_handle = cStringIO.StringIO()
    #create the csv output object
    csv_output = csv.writer(csv_handle)
    value_list = [] 
    for field in model._meta.fields:
        #if the field is a related field (ForeignKey, ManyToMany, OneToOne)
        if isinstance(field, RelatedField):
            #get the related model from the field object
            related_model = field.rel.to
            for key in row.__dict__.keys():
                #find the field in the row that matches the related field
                if key.startswith(field.name):
                    #Get the unicode version of the row in the related model, based on the id
                    try:
                        entry = related_model.objects.get(
                            id__exact=int(row.__dict__[key]),
                            )
                    except:
                        pass
                    else:
                        value = entry.__unicode__().encode("utf-8")
                        break
        #if it isn't a related field
        else:
            #get the value of the field
            if isinstance(row.__dict__[field.name], basestring):
                value = row.__dict__[field.name].encode("utf-8")
            else:
                value = row.__dict__[field.name]
        value_list.append(value)
    #add the row of csv values to the csv file
    csv_output.writerow(value_list)
    #Return the string value of the csv output
    return csv_handle.getvalue()

最佳答案

这里有一些可以流式传输 CSV 的简单代码;你可能可以从这里开始你需要做的任何事情:

import cStringIO as StringIO
import csv

def csv(request):
    def data():
        for i in xrange(10):
            csvfile = StringIO.StringIO()
            csvwriter = csv.writer(csvfile)
            csvwriter.writerow([i,"a","b","c"])
            yield csvfile.getvalue()

    response = HttpResponse(data(), mimetype="text/csv")
    response["Content-Disposition"] = "attachment; filename=test.csv"
    return response

这只是将每一行写入内存文件,读取该行并生成它。

此版本生成批量数据效率更高,但使用前请务必了解以上内容:

import cStringIO as StringIO
import csv

def csv(request):
    csvfile = StringIO.StringIO()
    csvwriter = csv.writer(csvfile)

    def read_and_flush():
        csvfile.seek(0)
        data = csvfile.read()
        csvfile.seek(0)
        csvfile.truncate()
        return data

    def data():
        for i in xrange(10):
            csvwriter.writerow([i,"a","b","c"])
        data = read_and_flush()
        yield data

    response = HttpResponse(data(), mimetype="text/csv")
    response["Content-Disposition"] = "attachment; filename=test.csv"
    return response

关于python - 在 Django 中流式传输 CSV 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5146539/

相关文章:

python - 删除 numpy 中的嵌套循环

python - 为什么从 sqlalchemy 调用的存储过程不起作用,但从工作台调用却起作用?

python - 获取集合中不包括某些元素的元素

python - 使用 html5 输入类型 ='color'

django {% url %} 标签不带参数

java - 如何更改此设置,使它无法实现我想要的方式?

javascript - 从excel复制粘贴,单元格换行符和行分隔符之间的区别

python - 将文本文件中的项目添加到 pyQt5 中的 QlistWidget

django admin 相关字段查找无效 : icontains

php - 基于数据表 Laravel 4 导出 CSV 或 PDF