我正在尝试根据 this V3 example 从复选框中过滤我的谷歌地图标记.我的复选框 html 是:
<form action="#">
Attractions: <input type="checkbox" id="attractionbox" onclick="boxclick(this,'attraction')" />
Food and Drink: <input type="checkbox" id="foodbox" onclick="boxclick(this,'food')" />
Hotels: <input type="checkbox" id="hotelbox" onclick="boxclick(this,'hotel')" />
Towns/Cities: <input type="checkbox" id="citybox" onclick="boxclick(this,'city')" /><br />
</form>
我的 javascript 在下面。我似乎无法让过滤器工作 - 目前所有标记都出现在 map 上,无论复选框的状态如何。我猜我只是把我的一些变量放在了错误的地方,但到目前为止我还没能解决这个问题!任何帮助将不胜感激。
var map;
var infowindow;
var image = [];
var gmarkers = [];
image['attraction'] = 'http://google-maps-icons.googlecode.com/files/beach.png';
image['food'] = 'http://google-maps-icons.googlecode.com/files/restaurant.png';
image['hotel'] = 'http://google-maps-icons.googlecode.com/files/hotel.png';
image['city'] = 'http://google-maps-icons.googlecode.com/files/smallcity.png';
function mapInit(){
var centerCoord = new google.maps.LatLng(18.23, -66.39);
var mapOptions = {
zoom: 1,
center: centerCoord,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("map"), mapOptions);
google.maps.event.addListener(map, 'click', function() {
infowindow.close();
});
jQuery.getJSON("/places", function(json) {
if (json.length > 0) {
for (i=0; i<json.length; i++) {
var place = json[i];
var category = json[i].tag;
addLocation(place,category);
}
}
});
function addLocation(place,category) {
var marker = new google.maps.Marker({
position: new google.maps.LatLng(place.lat, place.lng),
map: map,
title: place.name,
icon: image[place.tag]
});
marker.mycategory = category;
gmarkers.push(marker);
google.maps.event.addListener(marker, 'click', function() {
if (infowindow) infowindow.close();
infowindow = new google.maps.InfoWindow({
content: "<h3>"+ place.name +"</h3><p>" + place.tag +"</p><a href='/places/"+place.id+"'>Show more!</a>"
});
infowindow.open(map, marker);
});
}
function show(category) {
for (var i=0; i<gmarkers.length; i++) {
if (gmarkers[i].mycategory == category) {
gmarkers[i].setVisible(true);
}
}
document.getElementById(category+"box").checked = true;
}
function hide(category) {
for (var i=0; i<gmarkers.length; i++) {
if (gmarkers[i].mycategory == category) {
gmarkers[i].setVisible(false);
}
}
document.getElementById(category+"box").checked = false;
infowindow.close();
}
function boxclick(box,category) {
if (box.checked) {
show(category);
} else {
hide(category);
}
}
}
jQuery(document).ready(function(){
mapInit();
});
最佳答案
您的问题是 boxclick()
函数包含在 mapInit()
函数的范围内,因此 boxclick()
无法从 mapInit()
外部访问。您应该从 HTML 输入字段中删除 onclick
事件,然后在 mapInit()
函数中定义事件处理程序,如下所示:
function mapInit() {
// ...
$('#attractionbox').click(function () {
boxclick(this, 'attraction');
});
}
关于javascript - 使用复选框过滤谷歌地图标记,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3324573/