<script type= "text/javascript">
var url = "http://gdata.youtube.com/feeds/api/videos/VA770wpLX-Q?v=2&alt=json-in-script&callback=";
var title;
var description;
var viewcount;
var views;
var author;
$.getJSON(url,
function(data){
title = data.entry.title.$t;
description = data.entry.media$group.media$description.$t;
viewcount = data.entry.yt$statistics.viewCount;
views = numberFormat (viewcount);
author = data.entry.author[0].name.$t;
listInfo (title,description,author,views);
});
</script>
这就是我从单个视频中获取信息的代码，在收到信息后，它会调用此函数来显示它:
<script type="text/javascript">
function listInfo (title,description,author,views) {
var html = ['<dl>'];
html.push('<dt>','<span class="titleStyle">', title,'</span><span class="descriptionStyle">',description, '</span><span class="authorStyle">',author,'</span><span class="viewsStyle">',' Views:',views,'</span></dt>');
html.push('</dl>');
document.getElementById("agenda").innerHTML = html.join("");
}
function numberFormat(nStr,prefix){
var prefix = prefix || '';
nStr += '';
x = nStr.split('.');
x1 = x[0];
x2 = x.length > 1 ? '.' + x[1] : '';
var rgx = /(\d+)(\d{3})/;
while (rgx.test(x1))
x1 = x1.replace(rgx, '$1' + ',' + '$2');
return prefix + x1 + x2;
}
</script>
之后它将定义列表放入一个 div 中，我在一个表中放置了它
<table width="485"><tr><td><div id="agenda"></div></td></tr></table>
所有这些信息都在 body 中找到，我似乎无法让它发挥作用，我已经尝试了一个星期了，但我找不到任何方法让它发挥作用
最佳答案
由于 youtube API 不允许在单个请求中返回超过 50 条评论，因此您需要添加一个名为“start-index”的 URL 参数，它告诉 youtube 您希望从那里开始获取评论.下面是一个例子。我已经做到只要响应 JSON 返回 50 条评论，它就会为接下来的 50 条评论再次调用该函数。
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.5.1.min.js"></script>
<script type= "text/javascript">
function getYouTubeInfo() {
$.ajax({
url: "http://gdata.youtube.com/feeds/api/videos/<?php echo $_GET['v']; ?>?v=2&alt=json",
dataType: "jsonp",
success: function (data) { parseresults(data); }
});
}
function parseresults(data) {
var title = data.entry.title.$t;
var description = data.entry.media$group.media$description.$t;
var viewcount = data.entry.yt$statistics.viewCount;
var author = data.entry.author[0].name.$t;
$('#title').html(title);
$('#description').html('<b>Description</b>: ' + description);
$('#extrainfo').html('<b>Author</b>: ' + author + '<br/><b>Views</b>: ' + viewcount);
getComments(data.entry.gd$comments.gd$feedLink.href + '&max-results=50&alt=json', 1);
}
function getComments(commentsURL, startIndex) {
$.ajax({
url: commentsURL + '&start-index=' + startIndex,
dataType: "jsonp",
success: function (data) {
$.each(data.feed.entry, function(key, val) {
$('#comments').append('<br/>Author: ' + val.author[0].name.$t + ', Comment: ' + val.content.$t);
});
if ($(data.feed.entry).size() == 50) { getComments(commentsURL, startIndex + 50); }
}
});
}
$(document).ready(function () {
getYouTubeInfo();
});
</script>
<title>YouTube</title>
</head>
<body bgcolor="grey">
<div align="center">
<br/><br/>
<div id="title" style="color: #dddddd">Could not find a title</div><br/>
<iframe title="Youtube Video Player" width="640" height="390" src="http://www.youtube.com/embed/<?php echo $_GET['v']; ?>?fs=1&autoplay=1&loop=0" frameborder="0" allowfullscreen style="border: 1px solid black"></iframe>
<br/><br/>
<div id="description" style="width:400px; background-color: #dddddd; font-size:10px; text-align:left;">Could not find a description</div>
<div id="extrainfo" style="width:400px; background-color: #dddddd; font-size:10px; text-align:left;">Could not find extra information</div>
<div id="comments" style="width:400px; background-color: #dddddd; font-size:10px; text-align:left;">Could not find comments</div>
</div>
</body>
</html>
如果您有任何问题或遇到此代码问题，请不要犹豫，再次提问 :-)
祝你好运， 汤姆
关于javascript - 使用 javascript/jquery 获取 Youtube 视频信息，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/5194619/