php - 通过 PHP 清理 PostgreSQL 中所有用户的输入

Question

本题基于this thread .

使用 pg_prepare 时是否需要显式清理？

我觉得 pg_prepare 会自动清理用户的输入，所以我们不需要这个

 $question_id = filter_input(INPUT_GET, 'questions', FILTER_SANITIZE_NUMBER_INT);

我使用 Postgres 的环境

 $result = pg_prepare($dbconn, "query9", "SELECT title, answer
     FROM answers 
     WHERE questions_question_id = $1;");                                  
 $result = pg_execute($dbconn, "query9", array($_GET['question_id']));

Answer 1

根据 Postgres documentation在 pg_prepare 上，所有转义都已为您完成。请参阅示例部分，其中列出了以下代码(包括注释):

<?php
// Connect to a database named "mary"
$dbconn = pg_connect("dbname=mary");

// Prepare a query for execution
$result = pg_prepare($dbconn, "my_query", 'SELECT * FROM shops WHERE name = $1');

// Execute the prepared query.  Note that it is not necessary to escape
// the string "Joe's Widgets" in any way
$result = pg_execute($dbconn, "my_query", array("Joe's Widgets"));

// Execute the same prepared query, this time with a different parameter
$result = pg_execute($dbconn, "my_query", array("Clothes Clothes Clothes"));
?>

尽管注意它们在查询字符串周围使用单引号 (') 而不是双引号 (") 可能很有用，例如 $1 不会意外插入到字符串中。