PHP - 使用有效的访问 token 通过 Graph API 在 Facebook 上发布视频

Question

我的服务器上有一个视频， 我需要使用 Graph API 在 Facebook 上发布该视频。

Here是 Facebook 团队建议的代码。

我正在做的如下。

1) 我从 Android 设备获取访问 token

2) 通过将该访问 token 传递给 Facebook 并获取电子邮件 ID 并通过电子邮件 ID 识别用户来识别用户

3) 通过 Graph API 将用户的视频从我的服务器发布到 Facebook。

4) 将视频 ID 作为 API 响应返回到 android 设备。

我正在接近这条路线，因为在 Android 设备中，在 Facebook 上发布视频是两步过程。

1)先下载视频

2) 发布到 Facebook

这很耗时。

这是我正在尝试的代码

    define("FB_WEB_APP_ID","********");
    define("FB_WEB_SECRET","********");
    define("FB_WEB_REDIRECT_URI","<< redirect url >>");
    $GLOBALS["all_user_dir_path"]="/var/www/proj/web/video/user_videos/";
     define("FB_WEB_SCOPE","user_friends,email,public_profile,user_hometown,user_location,user_photos,user_videos,publish_actions,read_friendlists,publish_stream,offline_access");
    define("FB_WEB_RESPONSE_TYPE","code%20token");

    $GLOBALS["fb_app_creds"]=array();
    $GLOBALS["fb_app_creds"]['appId']= FB_WEB_APP_ID;
    $GLOBALS["fb_app_creds"]['secret']=FB_WEB_SECRET;
    $GLOBALS["fb_app_creds"]['response_type']=FB_WEB_RESPONSE_TYPE;
    $GLOBALS["fb_app_creds"]['redirect_uri']=FB_WEB_REDIRECT_URI;
    $GLOBALS["fb_app_creds"]['scope']=FB_WEB_SCOPE;
    $GLOBALS["facebook"] = new Facebook($GLOBALS["fb_app_creds"]);



class DefaultController extends Controller
{
// some code....

/**
     * @Route("/gk",name="_fb")
     * @Template()
     */
    public function gkAction(Request $request){

        $facebook = $GLOBALS["facebook"];

        $access_token=$request->query->get("access_token");

        if(!$access_token){
          die("give access token in url.......");
        }

        echo "<pre>";
        $facebook->setAccessToken($access_token);

        $user = $facebook->getUser();

        $me=$facebook->api("/me");

        $email=$me['email'];

        $all_user_dir_path=$GLOBALS["all_user_dir_path"];
        $user_directory = str_replace(array(".","@"), "_",$email);

        $user_dir_abs_path=$all_user_dir_path.$user_directory;

        print_r($me);

        $video_file_path=$user_dir_abs_path."/video.mp4";

        if(file_exists($video_file_path))
        { 
          echo "file exists...";
        }else{
          die("not exist");
        }

        $video_title="Test";
        $video_desc="Test";

        $access_token=$request->query->get("access_token");

        $file = "@".$video_file_path;
        $data =  array('name' => 'file', 'file' => $file);

          $post_url = "https://graph-video.facebook.com/me/videos?"
         . "title=" . $video_title. "&description=" . $video_desc
         . "&". $access_token
         ;


        echo "<hr>TRY 1<hr>";
        try{
            $ch = curl_init();
            curl_setopt($ch, CURLOPT_URL, $post_url);
            curl_setopt($ch, CURLOPT_POST, 1);
            curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
            curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
            $res = curl_exec($ch);

            $video_id=0;
            if( $res === false ) {

            }else{
              $res=json_decode($res,true);
              /* $video_id = $res['id'];*/
               echo ":::: ";print_r($res);
            }
            curl_close($ch);
       }catch(\Exception $e){
           echo " Exception generated in Try 1 : ".$e->getMessage();
       }

       echo "<hr>TRY 2<hr>";

       $params = array(
            "access_token" => $access_token,
            "name"=>"file",
            "file" => "@".$video_file_path,
            "title" => $video_title,
            "description" => $video_desc
          );
          try {
              $ret = $facebook->api('/me/videos', 'POST', $params);
              print_r($ret);
          } catch(\Exception $e) {
            echo " Exception generated in Try 2 : ".$e->getMessage();
          } 

        die("</pre>");
    }    

}

我得到的输出是 An active access token must be used to query information about the current user.错误和(#353) You must select a video file to upload.

看这张图

请告诉我如何解决这个问题？？

尝试了新代码...................................................... …………

 /* code with sdk - object oriented way */
        $file=$GLOBALS["all_user_dir_path"].$user_directory."/video.mp4";
        $source = array();
        $source['name']="video.mp4";
        $source['type'] = "video/mp4";
        $source['tmp_name'] = $file;
        $source['error'] = 0;
        $source['size'] = filesize($file);
        echo "<br><br>$file<br><br>";

        $params = array(
          "access_token" => $access_token, 
            "source" => $source,
            "title" => "testvideo",
            "description" => "testvideo"
        );
          try {
              $ret = $facebook->api('/me/videos', 'POST', $params);
              echo 'Successfully posted to Facebook';
              echo "<pre>";print_r($ret);echo "</pre>";
          } catch(Exception $e) {
            echo $e->getMessage();
          } 

但这给出了 (#353) You must select a video file to upload错误

Answer 1

答案在这里

public function shareSocialgrationFB($access_token,& $exception){
        $video_id=0;

        try{
            $config = array();
            $config['appId'] = FB_WEB_APP_ID;
            $config['secret'] = FB_WEB_SECRET;
            $config['fileUpload'] = true; 
            $config['cookie'] = true;
            $facebook = new Facebook($config);
            $facebook->setFileUploadSupport(true);  
            $facebook->setAccessToken($access_token);

            $me=$facebook->api("/me");
            $email=$me['email'];

            $user_directory = str_replace(array(".","@"), "_",$email);

            $file = $GLOBALS["all_user_dir_path"].$user_directory."/video.mp4";

            $usersFacebookID=$facebook->getUser();
            $video_details = array(   
                      'access_token'=> $access_token,
                      'message'=> 'Testvideo!',
                      'source'=> '@' .realpath($file),
                      'title'=>'Test'   
            );
            $post_video = $facebook->api('/'.$usersFacebookID.'/videos', 'post', $video_details);
            $video_id=$post_video['id'];
        }catch(\Exception $e){
            //echo "Exception generated :: ".$e->getMessage(); 
        $exception=$e->getMessage(); 
        // extra code to handle exception
        }
        return $video_id;
    }

引用:How to POST video to Facebook through Graph API using PHP

我不知道为什么关于配置的信息

$config['fileUpload'] = true; 
$config['cookie'] = true;

在下面的 API 官方文档中没有提到

https://developers.facebook.com/blog/post/493/

https://developers.facebook.com/docs/graph-api/reference/v2.0/user/videos#publish

但是上面给出的解决方案对我来说效果很好。