php - 使用抽象参数实例化对象

Question

interface aInterface{
     public function __construct(aClass_Abstract $a, bClass_Abstract $b){
     }
}
class Sample implements aInterface
{
     public function __construct(aClass_Abstract $a, bClass_Abstract $b){
         //implementation
         $this->init();
     }
     public function init(){
         //implementation
     }
}

如何在使用 PHPUnit 进行测试时设置它？

...实现... 测试

...
function setUp(){
    //initialize
}

Answer 1

简而言之:使用 getMockForAbstractClass创建一个 fake instance您需要传递的类的数量，以便您可以测试它们。

$a = $this->getMockForAbstractClass("aClass_Abstract");
$b = $this->getMockForAbstractClass("bClass_Abstract");
$class = new Sample($a, $b);

完整代码示例

(修复接口(interface)定义)

<?php

interface aInterface{
     public function __construct(aClass_Abstract $a, bClass_Abstract $b);
}
class Sample implements aInterface
{
     public function __construct(aClass_Abstract $a, bClass_Abstract $b){
         //implementation
         $this->a = $a;
     }
     public function init(){
         return $this->a->myMethod();
     }
}

abstract class aClass_Abstract {
    abstract public function myMethod();
}

abstract class bClass_Abstract {}

class SampleTest extends PHPUnit_Framework_TestCase {

    public function testSetup() {

        $a = $this->getMockForAbstractClass("aClass_Abstract");
        $a->expects($this->once())->method("myMethod")->will($this->returnValue(true));
        $b = $this->getMockForAbstractClass("bClass_Abstract");
        $class = new Sample($a, $b);
        $this->assertTrue($class->init());

    }
}


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