php - 将 PHP curl_setopt() 转换为 Python 请求和 CLI curl

Question

我正在尝试将以下 PHP curl_setopt() 转换为 Python Requests 中的等效项 以及 CLI curl。对于 Python，如果在 Requests 中不可能, 我会使用 pycurl .

curl_setopt($process, CURLOPT_RETURNTRANSFER, true);
curl_setopt($process, CURLOPT_SSL_VERIFYPEER, false);

这是有效的 PHP curl 代码:

$params = array(
    'username' => $username,
    'password' => $password
);

$params_string = json_encode($params);

$process = curl_init($url);
curl_setopt($process, CURLOPT_RETURNTRANSFER, true);
curl_setopt($process, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($process, CURLOPT_POSTFIELDS, $params_string);

$headers = array();
$headers[] = 'Content-Type: application/json';
curl_setopt($process, CURLOPT_HTTPHEADER, $headers);

$data = curl_exec ($process);

curl_close ($process);   

我不知道我需要在 Python 请求 中为这两个 PHP curl_setopt(s) 设置什么。

我在 CLI curl 中尝试了以下操作，但出现了一个Bad Request 错误:

AUTHENTICATE_DATA="usename=${USERNAME}&password=${PASSWORD}"

AUTHENTICATE_RESPONSE=$(curl \
  -X POST \
  -H 'Content-Type: application/json' \
  --data-urlencode "${AUTHENTICATE_DATA}" \
  -v \
  ${AUTHENTICATE_URL})

echo ${AUTHENTICATE_RESPONSE}

我需要什么？

谢谢，感谢您的帮助。

Answer 1

使用请求:

import requests

url = 'https://...'
username = 'username'
password = 'supersecret'

# curl_setopt($process, CURLOPT_RETURNTRANSFER, true);
# PHP bashing time: Who in their right minds would create a function
# that spews its return value to stdout by default, unless explicitly
# instructed not to do so.
resp = requests.post(

    # $process = curl_init($url);
    url,

    # $params = array(
    #    'username' => $username,
    #    'password' => $password
    # );
    # $params_string = json_encode($params);
    # curl_setopt($process, CURLOPT_POSTFIELDS, $params_string);
    # $headers[] = 'Content-Type: application/json';
    # curl_setopt($process, CURLOPT_HTTPHEADER, $headers);
    json=dict(username=username, password=password),

    # curl_setopt($process, CURLOPT_SSL_VERIFYPEER, false);
    # note: you shouldn't do this, really
    verify=False,

)

data = resp.text
# or if you expect json response
data = resp.json()