我正在使用 dojo 和 ajax 向 PHP 发送时间戳，PHP 会执行数据库检查，然后返回时间戳以用于调试目的。当我发送这个时间戳时，它是一个数字，当它返回时，它是一个字符串。这有什么具体原因吗？我应该怎么做才能避免这种情况(在 PHP 中转换为 int，通过 JSON 修复，或在 javascript 中转换为 int)
这是道场代码
dojo.xhrGet({
url: 'database/validateEmail.php',
handleAs: "json",
content: {
email : 'George.Hearst@Pinkerton.dw',
time: 0
},
load: function(args) {/*SEE BELOW*/}
});
这是PHP脚本
<?php
/**
** connect to the MySQL database and store the return value in $con
*
*/
$con = mysql_pconnect("localhost:port", "username", "password");
/**
** handle exceptions if we could not connect to the database
*
*/
if (!$con) {
die('Could not connect: ' . mysql_error());
}
/**
** Create table query
*
*/
mysql_select_db("portal", $con);
/**
** Get user entered e-mail
*
*/
$emailQuerry = mysql_num_rows(mysql_query("SELECT EMAIL FROM user WHERE EMAIL='" . $_GET["email"] . "'")) == 1;
/**
** Whether successful or not, we will be returning the time stampe (this is used to determine whether there were any changes between the time a request
** was sent, and when this response was returned.
*
*/
$result['time'] = $_GET["time"];
/**
** Currently only checks to see if the two values were provided. Later, will have to check against passwords
*
*/
if ($emailQuerry) {
$result['valid'] = true;
}
else {
$result['valid'] = false;
}
echo json_encode($result);
?>
最后加载函数在上面留空
load: function(args) {
console.log(localArgs.time + ' v ' + args.time);
console.log(localArgs.time === args.time);
console.log(localArgs.time == args.time);
}
其输出为
0 v 0
false
true
最佳答案
json_encode 将所有变量编码为字符串。
因此 javascript 会将其视为字符串。
所以在 javascript 中你可以使用parseInt(...)
关于php - PHP 会自动将数字转换为字符串吗？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7967878/