php - 只为 foreach 循环显示一条消息

Question

当循环通过下面的 foreach 循环时，每次执行循环时我都会得到一个 echo 输出。我怎样才能将这些消息减少到只有一条最终消息？

即如果只有"success messages" then echo "Success"，如果发生错误("fail"or "nothing saved"message) then echo “失败”。一旦发生错误，循环将不会停止，而是完全继续进行。最后我只想知道是否发生错误或结果未保存。

if(!isset($_POST["submitbutton"])) {
  echo "Click this button to save your input.";
} else {
  foreach($_POST['tipp_id'] as $key => $tipp_id) {
    if($tipp_id > 0) {
      $result="
      //SQL query
      ";
      $query=mysqli_query($conn,$result);
      if($query) {
        echo "Success.<br>";
      } else {
        echo "Fail.<br>";
      }
    } else {
      echo "Nothing saved.";
    }
  }
}

Answer 1

您可以创建一个数组和一些计数变量来获取成功/失败计数以及哪个查询不成功。

<?php
$failed_query = array(); // create an empty array to get which query fails
$failed_count = 0; // count to come to know how many query failed
$success_count = 0; // count to come to know how many query succeed
if(!isset($_POST["submitbutton"])) {
  echo "Click this button to save your input.";
}else {
  foreach($_POST['tipp_id'] as $key => $tipp_id) {
    if($tipp_id > 0) {
      $result="//SQL query";
      $query=mysqli_query($conn,$result);
      if($query) { // if query runs
        $success_count++; // increase success counter
      } else {
        $failed_count++; // increase failed counter
        $failed_query[] = $result; // insert failed query to the array
      }
    }
  }
}
if($success_count > $failed_count){
    echo "final output is success";
 }else{
   echo "final output is failed";
 }
echo "query executed successfully(Number)".$success_count;
echo "query execution failed(Number)".$failed_count;
echo "Failed queries are <br/>";
echo "<pre/>";print_r($failed_query);
?>

注意:-

1.您将以成功或失败的形式获得您想要的最终状态。

2.它会让您清楚地了解有多少查询执行成功，有多少失败。

3.您还可以检查哪些查询失败以及原因(通过检查失败的数组)