$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";
if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}
我在寻找什么 if
语句?
最佳答案
考虑到以下两个变量,我想一个解决方案可能是:
$textone = "pate";
$texttwo = "tape";
1.首先,拆分字符串,得到两个字母数组:
$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);
请注意,正如@Mike 在他的评论中指出的,而不是使用 preg_split()
就像我第一次做的那样,对于这种情况,最好使用 str_split()
:
$arr1 = str_split($textone);
$arr2 = str_split($texttwo);
2. 然后,对这些数组进行排序,使字母按字母顺序排列:
sort($arr1);
sort($arr2);
3. 之后,内爆数组,创建所有字母都按字母顺序排列的单词:
$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);
4. 最后,比较这两个词:
if ($text1Sorted == $text2Sorted) {
echo "$text1Sorted == $text2Sorted";
}
else {
echo "$text1Sorted != $text2Sorted";
}
将这个想法转化为比较函数会得到以下代码部分:
function compare($textone, $texttwo) {
$arr1 = str_split($textone);
$arr2 = str_split($texttwo);
sort($arr1);
sort($arr2);
$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);
if ($text1Sorted == $text2Sorted) {
echo "$text1Sorted == $text2Sorted<br />";
}
else {
echo "$text1Sorted != $text2Sorted<br />";
}
}
并在你的两个词上调用该函数:
compare("pate", "tape");
compare("pate", "tapp");
会得到以下结果:
aept == aept
aept != appt
关于php - 如何检查两个字符串是否包含相同的字母?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6807864/