php - 以标题行为键的 CSV 到 Json

Question

我想将 CSV 转换为 Json，使用标题行作为键，每一行作为对象。我该怎么做？

--------------------------------CSV------------ ----------------------

 InvKey,DocNum,CardCode
 11704,1611704,BENV1072
 11703,1611703,BENV1073

--------------------------------PHP------------ ------------------------

  if (($handle = fopen('upload/BEN-new.csv'. '', "r")) !== FALSE) {
       while (($row_array = fgetcsv($handle, 1024, ","))) {
            while ($val != '') {
                foreach ($row_array as $key => $val) {
                        $row_array[] = $val;
                        }
                }
            $complete[] = $row_array;   
            }
            fclose($handle);
        }
        echo json_encode($complete);

Answer 1

只需单独读取第一行并将其合并到每一行:

if (($handle = fopen('upload/BEN-new.csv', 'r')) === false) {
    die('Error opening file');
}

$headers = fgetcsv($handle, 1024, ',');
$complete = array();

while ($row = fgetcsv($handle, 1024, ',')) {
    $complete[] = array_combine($headers, $row);
}

fclose($handle);

echo json_encode($complete);