php - 无法将 JSON 解码为 PHP 数组并显示在 HTML 表中

标签 php html arrays json html-table

我有这个 json 数据

{
   "next_offset": -1,
   "records":    [
            {
         "id": "87dad127-a60e-15a3-148e-56c7675f11df",
         "name": "1A Unit",
         "suite": "1A",
         "sf": 1200,
         "unit_floor": 1,
      },
            {
         "id": "f386a7ad-d6ea-6eb1-9b8f-56cd6104c445",
         "name": "3B Unit",
         "suite": "3B",
         "sf": 450,
         "unit_floor": 3,
      },
            {
         "id": "b352dc84-8c76-6c27-daa4-56cd61e71aa2",
         "name": "3A Unit",
         "suite": "3A",
         "sf": 450,
         "unit_floor": 3,
      },
            {
         "id": "8ec4325a-1271-560e-888b-56cd6120f5de",
         "name": "2B Unit",
         "suite": "2B",
         "sf": 450,
         "unit_floor": 2,
      },
            {
         "id": "5a15fd5e-246a-be4b-fd5d-56cd619e9ee1",
         "name": "1B Unit",
         "suite": "1B",
         "sf": 450,
         "unit_floor": 1,
      },
            {
         "id": "61a55092-5683-1088-2d6c-56c99c5d4873",
         "name": "2A Unit",
         "suite": "2A",
         "sf": 3000,
         "unit_floor": 2,
      }
   ]
}

我想根据楼层数在表格中显示此数据。像三楼单元 3A、3B 及其面积总和(以平方英尺为单位)排成一排,二楼单元 2A、2B 及其面积总和排成一排,一楼单元 1A、1B 及其面积总和排成一排。请帮助我。

我试过了,但没有给出预期的结果

$unit_response = call($url, $oauth2_token_response->access_token, 'GET');

        $unit_json = json_decode(json_encode($unit_response),true);
    <table class="stak-plan">

                <?php foreach ($unit_json['records'] as $unit_data) { ?>

                <tr>
                    <td>Floor: 3</td>
                    <td> 
                        Suit : <?php echo $unit_data['name'] ?><br>
                        SF : <?php echo $unit_data['sf'] ?>
                    </td>
                    <td>Suite: 3B<br /> SF: 25,000</td>
                    <td>Suite: 3C<br /> SF: 25,000</td>
                    <td> 
                    </td>
                </tr>  
                <?php } ?>

                </table>

这是预期的输出。 Output

最佳答案

CSS:

<style>
    td{
        border: 1px solid black;
        padding: 15px;
    }
</style>

JSON(一些额外的逗号已被删除):

$json = '{
    "next_offset": -1,
    "records":    [
             {
          "id": "87dad127-a60e-15a3-148e-56c7675f11df",
          "name": "1A Unit",
          "suite": "1A",
          "sf": 1200,
          "unit_floor": 1
       },
             {
          "id": "f386a7ad-d6ea-6eb1-9b8f-56cd6104c445",
          "name": "3B Unit",
          "suite": "3B",
          "sf": 450,
          "unit_floor": 3
       },
             {
          "id": "b352dc84-8c76-6c27-daa4-56cd61e71aa2",
          "name": "3A Unit",
          "suite": "3A",
          "sf": 450,
          "unit_floor": 3
       },
             {
          "id": "8ec4325a-1271-560e-888b-56cd6120f5de",
          "name": "2B Unit",
          "suite": "2B",
          "sf": 450,
          "unit_floor": 2
       },
             {
          "id": "5a15fd5e-246a-be4b-fd5d-56cd619e9ee1",
          "name": "1B Unit",
          "suite": "1B",
          "sf": 450,
          "unit_floor": 1
       },
             {
          "id": "61a55092-5683-1088-2d6c-56c99c5d4873",
          "name": "2A Unit",
          "suite": "2A",
          "sf": 3000,
          "unit_floor": 2
       }
    ]
 }';

PHP:

    $jd = json_decode($json);
    $floors = array();
    foreach ($jd->records AS $key => $obj) {
        $f = $obj->unit_floor;
        $id = $obj->id;
        $name = $obj->name;
        $suite = $obj->suite;
        $sf = $obj->sf;
        $floors[$f][$suite]['name'] = $name;
        $floors[$f][$suite]['id'] = $id;
        $floors[$f][$suite]['sf'] = $sf;
    }
    //sort floors in desc order
    krsort($floors);
    foreach($floors as $id => $floor){
        ksort($floors[$id]);
    }
    print '<table>';
    foreach($floors as $floor => $suites){
        $sqf = 0;
        print '<tr>';
            print '<td>FLOOR: '.$floor.'</td>';
            foreach($suites AS $suite => $value){
                $sqf += $value['sf'];
                print '<td>Suite: '.$suite.'<br>SF: '.$value['sf'].'</td>';
            }
            print '<td>'.$sqf.'</td>';
        print '</tr>';
    }
    print '</table>';

输出:

enter image description here

关于php - 无法将 JSON 解码为 PHP 数组并显示在 HTML 表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35630054/

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