php - 使用 fopen() 包装器创建 ZIP 文件

Question

如何使用 fopen() wrapper 创建 ZIP 文件？这显然不是方式:

<?php

if( class_exists('ZipArchive') ){
    echo 'Class ZipArchive exists, generating file...' . PHP_EOL;

    $fp = fopen('zip://' . dirname(__FILE__) . '/test.zip', 'w');
    if($fp){
        fwrite($fp, 'Lorem ipsum dolor sit amet, consectetur adipisicing elit.');
        fclose($fp);
        echo 'Done' . PHP_EOL;
    }else{
        echo 'Could not open file' . PHP_EOL;
    }
}else{
    echo 'Class Zip is not available' . PHP_EOL;
}

...因为我得到的是:

Class ZipArchive exists, generating file...

Warning: fopen(zip://C:\tmp/test.zip) [http://es.php.net/function.fopen]: failed to open stream: operation failed in C:\tmp\test.php on line 6
Could not open file

Answer 1

我最终假设zip: wrapper 支持写入的说法是一个文档错误，reported it as such .错误报告已被接受并修复。