我有这段代码,并且我已经尝试了所有我能想到的方法来让它在我的 WAMP 本地服务器上运行任何帮助将不胜感激。我是 PHP 笨蛋。这适用于实时服务器,但不适用于我的 WAMP 服务器。我确实登录了,只是页面似乎没有将 session 变量传递给正确的用户级别。对于第一次的糟糕描述,这就是行不通的原因。
if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['login']))
{
if ($level == "Administrator") {
echo 'My Content';
}
elseif ($level == "Bank Officer") {
echo "";
}
elseif ($level == "Agent") {
echo "";
}
elseif(!empty($_POST['login']) && !empty($_POST['password']))
{
$login = mysql_real_escape_string($_POST['login']);
$password = $_POST['password'];
$checklevel = mysql_query("SELECT * FROM users WHERE login = '".$login."' AND password = '".$password."' ");
if(mysql_num_rows($checklevel) == 1)
{
$row = mysql_fetch_array($checklevel);
$level = $row['level'];
$_SESSION['level'] = $level;
}
$checklogin = mysql_query("SELECT * FROM users WHERE login = '".$login."' AND password = '".$password."' AND level='".$level."'");
if(mysql_num_rows($checklogin) == 1)
{
$row = mysql_fetch_array($checklogin);
$firstname = $row['firstname'];
$login = $row['login'];
$agent = $row['agent'];
$_SESSION['agent'] = $agent;
$_SESSION['firstname'] = $firstname;
$_SESSION['login'] = $login;
$_SESSION['LoggedIn'] = 1;
非常感谢您的帮助。
最佳答案
if ($_SESSION['level'] == "Bank Officer")
{
header('Location: index3.php');
exit;
}
elseif ($_SESSION['level'] == "Agent")
{
header('Location: index4.php');
exit;
}
elseif ($_SESSION['level'] == "Bank Manager")
{
header('Location: index5.php');
exit;
}
else
{
echo "Contact Administrator";
exit;
}
关于php - session 不适用于 wamp 但适用于实时服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13656952/