php - 链接中的 ZF2 路由无法正常工作

Question

我正在处理一个 Zend Framework 2 应用程序，我似乎无法在其中正确路由或不知道将其路由到何处。

我有一个主机名 => webapp.foo-bar.com。我们决定在末尾添加一个 Subhost =>/app/，这个应用程序的名称叫做 => app。我在页面上有一个链接，它的路径是 =>/graph/page-name。但是当我将鼠标悬停在看起来像这样的链接上时:

<a href="/graph/page-name">FooBar</a>

我会得到 webapp.foo-bar.com/graph/page-name 而不是 webapp.foo-bar.com/app/graph/page-name。

我的应用程序配置是:

<?php
/**
 * Zend Framework (http://framework.zend.com/)
 *
 * @link      http://github.com/zendframework/ZendSkeletonApplication for the canonical source repository
 * @copyright Copyright (c) 2005-2013 Zend Technologies USA Inc. (http://www.zend.com)
 * @license   http://framework.zend.com/license/new-bsd New BSD License
 */

return array(
    'router' => array(
        'routes' => array(
            'home' => array(
                'type' => 'hostname',
                'options' => array(
                    'route'    => 'webapp.foo-bar.com/app',
                    'defaults' => array(
                        '__NAMESPACE__' => 'Application\Controller',
                        'controller' => 'Index',
                        'action'     => 'index',
                    ),
                ),
            ),
        // The following is a route to simplify getting started creating
        // new controllers and actions without needing to create a new
        // module. Simply drop new controllers in, and you can access them
        // using the path /application/:controller/:action
        'application' => array(
            'type'    => 'Literal',
            'options' => array(
                'route'    => '/application',
                'defaults' => array(
                    '__NAMESPACE__' => 'Application\Controller',
                    'controller'    => 'Index',
                    'action'        => 'index',
                ),
            ),
            'may_terminate' => true,
            'child_routes' => array(
                'default' => array(
                    'type'    => 'Segment',
                    'options' => array(
                        'route'    => '/[:controller[/:action]]',
                        'constraints' => array(
                            'controller' => '[a-zA-Z][a-zA-Z0-9_-]*',
                            'action'     => '[a-zA-Z][a-zA-Z0-9_-]*',
                        ),
                        'defaults' => array(
                        ),
                    ),
                ),
            ),
        ),
    ),
),
'service_manager' => array(
    'abstract_factories' => array(
        'Zend\Cache\Service\StorageCacheAbstractServiceFactory',
        'Zend\Log\LoggerAbstractServiceFactory',
    ),
    'aliases' => array(
        'translator' => 'MvcTranslator',
    ),
),
'translator' => array(
    'locale' => 'en_US',
    'translation_file_patterns' => array(
        array(
            'type'     => 'gettext',
            'base_dir' => __DIR__ . '/../language',
            'pattern'  => '%s.mo',
        ),
    ),
),
'controllers' => array(
    'invokables' => array(
        'Application\Controller\Index' => 'Application\Controller\IndexController'
    ),
),
'view_manager' => array(
    'display_not_found_reason' => true,
    'display_exceptions'       => true,
    'doctype'                  => 'HTML5',
    'not_found_template'       => 'error/404',
    'exception_template'       => 'error/index',
    'template_map' => array(
        'layout/layout'           => __DIR__ . '/../view/layout/layout.phtml',
        'application/index/index' => __DIR__ . '/../view/application/index/index.phtml',
        'error/404'               => __DIR__ . '/../view/error/404.phtml',
        'error/index'             => __DIR__ . '/../view/error/index.phtml',
    ),
    'template_path_stack' => array(
        __DIR__ . '/../view',
    ),
),
// Placeholder for console routes
'console' => array(
    'router' => array(
        'routes' => array(
        ),
    ),
),
);

我看到有这样一个选项:

<a href="<?=$this->url('application/default', array('controller' => 'graph', 'action' => 'page-name')?>">FooBar</a>

这是否需要在每个链接上完成，或者我们是否能够在配置级别完成？

谢谢!

---

更新:

我已经设法让客户端使用 this->url() 方法关闭，一切看起来都很好。链接甚至在 jQuery 部分中也有效。关于指向另一个 Controller 的链接未显示链接中的操作，我遇到了一个小问题。

<a href="<?php echo $this->url('foo-bar', array('action' => 'bar-foo'))?>?year=2015"</a>

带回 webapp.foo-bar.com/app/foo-bar?year=2015。我希望它返回 webapp.foo-bar.com/app/foo-bar/bar-foo?year=2015。这是在foo-bar的Controller中配置还是在this-url()中可以配置？

感谢您提供的所有帮助。真的很欣赏!

Answer 1

如果两个应用共享同一个域，则您的配置无效。我的配置文件版本如下。

附言我创建了单独的模块示例，因此它不会干扰应用程序配置。

use Zend\Router\Http\Literal;
use Zend\Router\Http\Segment;
use \Sample\Controller\IndexController;
use Zend\ServiceManager\Factory\InvokableFactory;


return [
    'router' => [
        'routes' => [
            'v2' => [
                'type' => Segment::class,
                'options' => [
                    'route' => '/v2/app',
                    'defaults' => [
                        'controller' => IndexController::class,
                        'action' => 'index',
                    ],
                ],
                'child_routes' => [
                    'index' => [
                        'type' => Literal::class,
                        'options' => [
                            'route' => '/',
                            'defaults' => [
                                'controller' => IndexController::class,
                                'action' => 'index',
                            ],
                        ],
                    ],
                    'application' => [
                        'type' => Segment::class,
                        'options' => [
                            'route' => '[/:action]',
                            'defaults' => [
                                'controller' => IndexController::class,
                                'action' => 'index',
                            ],
                        ],
                    ]
                ],
            ],
        ],
    ],
    'controllers' => [
        'factories' => [
            IndexController::class => InvokableFactory::class,
        ],
    ],
    'view_manager' => [
        'template_path_stack' => [
            __DIR__ . '/../view',
        ],
    ],
];

这是创建指向该应用程序的链接的方式:

<?php echo $this->url("v2/application", ['action' => 'page-name']) ?>